- #1
i_hate_math
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Homework Statement
Consider a solution in which 99% of the atoms are 4He and 1% are 3He. Assuming that the 3He atoms behave as an ideal gas of spin-1/2 particles determine the Fermi energy of the 3He atoms. You may assume that one mole of 4He occupies a volume of 28 cm3.
Homework Equations
EF = h2/2m * (3π2n)2/3
The Attempt at a Solution
The density of 4He is calculated using its molar volume:
n4 = 2.151*1028 [m-3]
Assuming equilibrium, the concentration of 4He is:
x4 = n4/(n3+n4) = 0.01
=> n3 = n4/99
=> EF = h2/2m * (3π2n3)2/3
This approach seems too simple for an exam question on quantum gases as I haven't considered the fact that 4He are bosons and undergo BEC when T->0.