Thermodynamics - work in adiabatic, isothermal, isobaric

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SUMMARY

The discussion revolves around the work required by an external agent during the compression of an ideal gas under three different thermodynamic processes: adiabatic, isothermal, and isobaric. The user initially concluded that the ranking of work required is adiabatic, isothermal, and isobaric (choice A). However, the consensus indicates that the correct ranking is isobaric, isothermal, and adiabatic (choice E), due to the convention that work done on the system is considered negative, thus reversing the inequality of work done in each process.

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Homework Statement


21. A quantity of an ideal gas is compressed to half its initial volume. The process may be adiabatic, isothermal, or isobaric. Rank those three processes in order of the work required of an external agent, least to greatest.
A. adiabatic, isothermal, isobaric
B. adiabatic, isobaric, isothermal
C. isothermal, adiabatic, isobaric
D. isobaric, adiabatic, isothermal
E. isobaric, isothermal, adiabatic


Homework Equations





The Attempt at a Solution


If I graph these three curves on a P-V axes, it seems to me that the work by the external agent will be positive because the volume is getting smaller. Also, the work is like the area under the curve for any of these processes, and so I get it choice A as my answer.

The isobaric path encloses a rectangle, the isothermal a hyperbola and the adiabat, a path that encloses less area than the isothermal.

I'm only checking because the answer given is E. And I don't know where I'm going wrong.

Thanks a lot ahead of time.
 
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The problem lies in what you treat external work as. The most accepted convention-well at least in my part of the world-is that work energy coming in the system is negative hence the inequality you built would be reversed.Your logic seems good enough.
 

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