This suggests that both H and K are normal subgroups of L. What am I missing?

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SUMMARY

The discussion focuses on the properties of the matrix group L = { (a 0) (c d) : a,c,d ∈ R, ad ≠ 0} and its subgroups H and K. It is established that H = { (p 0) (p - q) q : p,q ∈ R, pq ≠ 0} is a normal subgroup of L, while K = { (1 0) (r 1) : r ∈ R} is not. The confusion arises from the behavior of conjugation within these subgroups, particularly in how the resulting matrices maintain their structure under multiplication and inversion.

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Question about matrix groups and conjugate subgroups?

This question concerns the group of matrices
L = { (a 0)
(c d) : a,c,d ∈ R, ad =/ 0}
under matrix multiplication, and its subgroups
H = { (p 0, (p - q) q) : p,q ∈ R, pq =/ 0} and K = { (1 0, r 1) : r ∈ R}Show that one of H and K is a normal subgroup of L and that the other is not.

Any pointers would be fantastic! Struggling and is from a previous assignment but just can't seem to figure this out?!
I understand that klk^-1 gives a lower triangular matric similar to L. Which would be this is a subgroup of L

But when i multiply together lhl-1 is seem to also get a lower traingular matrix?

Any pointer to where i am going wrong?
 
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It seems to me that for every $a$, $c$ and $d$ and for every $r$ there exists an $r'$ such that
\[
\begin{pmatrix}a&0\\c&d\end{pmatrix} \begin{pmatrix}1&0\\r&1\end{pmatrix} = \begin{pmatrix}1&0\\r'&1\end{pmatrix} \begin{pmatrix}a&0\\c&d\end{pmatrix}
\]
 

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