# This summation sums to zero. Why?

1. Feb 5, 2012

### S_David

Hi,

I am reading a paper, and at some point the authors claim that:

$$\sum_{m=1}^{L+1}\frac{\prod_{\substack{l=1\\l\neq m}}^{L+1}\frac{\lambda(m)}{\lambda(m)-\lambda(l)}}{\lambda^r(m)}=0$$

the question is HOW?

Any tiny hint will be highly appreciated.

Thanks

2. Feb 8, 2012

### Amir Livne

In general there is no equality.
It must depend on the definitions of λ, r and L.
Can you provide more details?

3. Feb 8, 2012

### S_David

Lambdas are positive numbers, r is between 1 and L. That is all

4. Feb 8, 2012

### Amir Livne

I don't think that is correct.

Define $\lambda(m)=m$, and pick $L=r=2$. Then
$$\frac{\frac{\lambda(1)}{\left(\lambda(1)-\lambda(2)\right)\left(\lambda(1)-\lambda(3)\right)}}{\lambda(1)^2}+\frac{\frac{\lambda(2)}{\left(\lambda(2)-\lambda(1)\right)\left(\lambda(2)-\lambda(3)\right)}}{\lambda(2)^2}+\frac{\frac{\lambda(3)}{\left(\lambda(3)-\lambda(1)\right)\left(\lambda(3)-\lambda(2)\right)}}{\lambda(3)^2}=\frac{1}{2}-\frac{1}{2}+\frac{1}{6}=\frac{1}{6}$$