Those Pictures (Representations) in QM and the density equations

Click For Summary
SUMMARY

The discussion focuses on the use of density equations in quantum mechanics, specifically within the Schrödinger and Heisenberg representations. The density equation presented, ##i \hbar \frac{d \sigma}{dt}=[\hat{H}, \sigma]##, is confirmed to be in the Schrödinger representation, where ##\sigma## represents the density matrix. The correlation functions discussed, including ##\langle \mathscr{L}_+(\tau)\mathscr{L}_-(0)\rangle## and the "double" correlation ##\langle \mathscr{L}_+(t)\mathscr{L}_+(t+\tau)\mathscr{L}_-(t+\tau)\mathscr{L}_-(t)\rangle##, illustrate the distinction between the two representations, with the latter being explicitly stated as belonging to the Heisenberg representation.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the Schrödinger and Heisenberg pictures.
  • Familiarity with density matrices and their role in quantum systems.
  • Knowledge of Hamiltonians and their application in quantum mechanics.
  • Basic grasp of correlation functions in quantum theory.
NEXT STEPS
  • Study the derivation and applications of density matrices in quantum mechanics.
  • Learn about the time evolution operator in quantum systems.
  • Explore the differences between the Schrödinger and Heisenberg representations in detail.
  • Investigate correlation functions and their significance in quantum mechanics.
USEFUL FOR

Students and researchers in quantum mechanics, particularly those studying atomic interactions and the mathematical frameworks of quantum theory.

Robert_G
Messages
36
Reaction score
0
Hi there:

I am reading a book (Atom-Photon interaction by Claude Cohen-Tannoudji, Page 448) and the following things gave a big headache.

(1) Is there a density equation in Schrödinger Picture. because I encounter one, like:
##i \hbar \frac{d \sigma}{dt}=[\hat{H}, \sigma]##
and ##\hat{H}## contains the Hamiltonian of the atom, photon, and there interaction. So this is in Schrödinger Representations. right?

(2) The correlation ##\langle \mathscr{L}_+(\tau)\mathscr{L}_-(0)\rangle## is calculated step by step, from the equation in (1). So this is also in Schrödinger Representation. But the "double" correlation ##\langle \mathscr{L}_+(t)\mathscr{L}_+(t+\tau)\mathscr{L}_-(t+\tau)\mathscr{L}_-(t)\rangle## is in Heisenberg Representation, and this is clearly stated in the book, because, as the book said, the operators in that "double" correlation are in Heisenberg Representation. So those two correlations are from different Represetations?

Ps: ##\mathscr{L}_+## is the atomic upper operator, and ##\mathscr{L}_-## is the atomic lower operator.

HELP ME!
 
Physics news on Phys.org
It's a rough journey to learn this things, oh, my brain.
 
(1) Supposing that sigma is the density matrix, yes, you are using the Schrödinger picture

(2) Expectation values don't really specify which picture is being used. You can convert between pictures by rearranging the time evolution operator: <C(t)> = tr{σ C(t)} = tr{σ U(t)+CU(t)} = tr {U(t)σU+(t) C} = tr {σ(t) C} = <C>t
 
  • Like
Likes   Reactions: 1 person

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
945
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K