Three identical blocks, each of mass 0.6 kg, are connected by light strings. Assume that they lie on a frictionless, horizontal surface and are observed to have an acceleration of 4.0 m/s2 under the action of a force F.
Calculate F and two tension forces Tbc and Tab
The Attempt at a Solution
by applying newton second law on each block and then by projection on xx axis, we get:
And then from (3) we have Tbc=m*a=0.6*4
From (1) we get -Tab=(m*a)-F