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## Homework Statement

Three identical blocks, each of mass 0.6 kg, are connected by light strings. Assume that they lie on a frictionless, horizontal surface and are observed to have an acceleration of 4.0 m/s2 under the action of a force F.

## Homework Equations

Calculate F and two tension forces T

_{bc}and T

_{ab}

## The Attempt at a Solution

by applying newton second law on each block and then by projection on xx axis, we get:

On A:

F-T

_{ab}=m*a----(1)

On B:

T

_{ab}-T

_{bc}=m*a----(2)

On C:

T

_{bc}=m*a----(3)

(1)+(2)+(3) [tex]\RightarrowF=3*m*a[/tex]

F=7.2N

And then from (3) we have T

_{bc}=m*a=0.6*4

T

_{bc}=2.4N

From (1) we get -T

_{ab}=(m*a)-F

-T

_{ab}= (0.6*4)-7.2

T

_{ab}=4.8N

#### Attachments

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