- #1

LCSphysicist

- 646

- 162

- Homework Statement
- Two positive ions and one negative ion are fixed at the vertices of

an equilateral triangle. Where can a fourth ion be placed, along the

symmetry axis of the setup, so that the force on it will be zero? Is

there more than one such place? You will need to solve something

numerically.

- Relevant Equations
- Coulomb's Law would be enough.

Actually we find the two position in the axis very easily, but, what am trying to find is if exist such position (Being the charge of the ions equal) away from the symmetry axis, but i really don't want to try find it numerically, it would be a disaster.

The only conclusion i got is, if such position exist, it should be somewhere in the red region of the figure:

The blue charge is negative

The red positive.

There is a way to prove if exist or not this position? Without the math would arise?

The only conclusion i got is, if such position exist, it should be somewhere in the red region of the figure:

The blue charge is negative

The red positive.

There is a way to prove if exist or not this position? Without the math would arise?