Three forces simultaneously acting on an object

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The problem involves calculating the acceleration of a 3.81 kg mass subjected to three forces: 10.5 N north, 19.3 N east, and 15.4 N south. The resultant force in the north-south direction is determined to be 4.9 N south. To find the acceleration, the relevant equation F=ma is applied, focusing solely on the forces acting in the plane without including gravitational force. The acceleration components ax and ay are calculated separately, ensuring proper sign conventions are maintained. The final step involves using these components to find the overall magnitude of the acceleration.
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Homework Statement



Forces of 10.5 N north, 19.3 N east, and 15.4 N south are simultaneously applied to a 3.81 kg mass as it rests on an air table. What is the magnitude of its acceleration?

Homework Equations



F=ma

The Attempt at a Solution


Well I got the resultant force for the y direction to be 4.9N South. And from here I have no idea what to do, I started drawing triangles of the forces and just placing diagonal lines just so i can connect them, while knowing I can't mathematically do that.

Thanks for the help!
 
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Using the relevant equation, find ay along North-south direction.
Similarly find ax.
ax and ay are perpendicular to each other. So find the resultant a.
 
would I use the force of gravity as a part of the ay force? So it would be 15.4 + (force gravity) - 10.5?
 
kathyt.25 said:
would I use the force of gravity as a part of the ay force? So it would be 15.4 + (force gravity) - 10.5?

I wouldn't think you would use gravity. This problem is looking acceleration in the plane (N/S & E/W).

You should just use the forces and mass the give you:

<br /> \left(\frac{ \sum F_{N,S}}{m}\right)^2+\left(\frac{\sum F_{E,W}}{m}\right)^2=a^2<br />

and make sure you keep you signs correct.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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