Threshold wavelength photoelectrons

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Homework Help Overview

The discussion revolves around the emission of photoelectrons from a surface with a specified threshold wavelength of 600 nm when illuminated by light of 400 nm. The participants explore the relationship between photon energy and wavelength in the context of the photoelectric effect.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the significance of the threshold wavelength and its relation to the work function. Questions are raised about the energy of emitted photoelectrons when using different wavelengths of light.

Discussion Status

There is an ongoing exploration of the concepts related to photon energy and the photoelectric effect. Some participants provide guidance on calculating photon energy and comparing different wavelengths, while others express confusion about the implications of the threshold wavelength.

Contextual Notes

Participants are considering the implications of using light at the threshold wavelength versus a shorter wavelength, and how this affects the energy of emitted photoelectrons. The discussion reflects a lack of consensus on the understanding of these concepts.

delongk
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With what speed will the fastest photoelectrons be emitted from a surface wih threshold wavelength of 600nm when the surface is illuminated with light of wavelength of 400nm?
 
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delongk said:
With what speed will the fastest photoelectrons be emitted from a surface wih threshold wavelength of 600nm when the surface is illuminated with light of wavelength of 400nm?

Do you know the significance of the information given by the "threshold wavelength"? If I used a 600 nm light, what would be the energy of the photoelectrons that are emitted?

Zz.
 
the energy would be equal to the work function at 600nm because when the wavelength is at the threshold the energy is always equal to the work function.
 
how does that help? i still don't understand.
 
delongk said:
how does that help? i still don't understand.

It tells you what the work function is.
 
Supplementing comments of ZapperZ and d_leet -

One must determine the energy of the 600 nm photon, and that is sufficient to liberate (remove) an electron (photoelectron), hence the threshold.

Calculate the energy of the 400 nm photon and compare to the energy of the 600 nm photon.

Remember, the shorter the wavelength, the higher the frequency, which means more energy.
 
E=hf. this is all you need
 

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