Throw a ball up how high does it go

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In summary, the question is asking for the maximum height reached by an object that is projected straight upward from the surface of Earth with an initial speed of 2.98 km/s. The solution involves using the equations for kinetic and potential energy, as well as taking into account the nearly constant value of gravity and the distance to the center of mass of the Earth. The potential energy for a mass at a distance r from the Earth can be calculated using the equation -GmM/r, assuming that the potential at infinity is 0.
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Zacthor
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An object is projected straight upward from the surface of Earth with an initial speed of 2.98 km/s. What is the maximum height it reaches?


Ok i know this seams like a really easy problem but i can't figure it out... since this question is from our chapter on gravity i have trued usuing is ke initial = potential energy final...
ke initial being(1/2 m v^2) and potential energy final being: (GMm/r^2)^1/2 M is the mass of the Earth and m is the mass of the ball
 
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  • #2
You're not going to throw the ball so high that its distance to the center of mass of the Earth will change by a significant percentage. g is nearly constant. Therefore PE at height h will be mgh.
 
  • #3
mikelepore said:
You're not going to throw the ball so high that its distance to the center of mass of the Earth will change by a significant percentage. g is nearly constant. Therefore PE at height h will be mgh.

he said 2.98 km/s. that will get you high enough for g get significantly smaller.

the potential energy for a mass at distance r from the Earth is -GmM/r, if the potential at infinity is 0, so there is both an initial and a final potential energy.
 

1. How does the height of a thrown ball change over time?

The height of a thrown ball follows a parabolic path, meaning it reaches a maximum height and then falls back to the ground. This is due to the force of gravity pulling the ball towards the earth.

2. What factors affect the height of a thrown ball?

The height of a thrown ball is affected by the initial velocity of the throw, the angle at which it is thrown, and the force of gravity. Air resistance may also play a small role in some cases.

3. Can you calculate the exact height a ball will reach when thrown?

Yes, the height a ball will reach when thrown can be calculated using the equation h = (vi^2 * sin^2(theta)) / 2g, where h is the height, vi is the initial velocity, theta is the angle of throw, and g is the acceleration due to gravity. However, this calculation assumes ideal conditions and may not always be accurate.

4. Does the mass of the ball affect how high it will go when thrown?

Yes, the mass of the ball does affect how high it will go when thrown. A heavier ball will require more force to reach the same height as a lighter ball. However, the shape and size of the ball may also play a role in its trajectory and should be considered as well.

5. How does the height a ball is thrown from affect its maximum height?

The initial height at which a ball is thrown does not affect its maximum height. This is because the ball's potential energy at the start of the throw is converted into kinetic energy, which determines the maximum height it will reach. However, the angle at which the ball is thrown may impact the distance it travels before reaching its maximum height.

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