Throw a ball up how high does it go

  • Thread starter Thread starter Zacthor
  • Start date Start date
  • Tags Tags
    Ball
Click For Summary
SUMMARY

An object projected straight upward from Earth's surface with an initial speed of 2.98 km/s can reach a significant height before gravitational acceleration decreases. The discussion emphasizes using kinetic energy (KE) and gravitational potential energy (PE) to determine maximum height, specifically applying the equations KE_initial = (1/2)mv^2 and PE_final = -GmM/r. The gravitational constant (G) and the mass of the Earth (M) are crucial for accurate calculations, as the potential energy changes with height.

PREREQUISITES
  • Understanding of gravitational potential energy and kinetic energy concepts
  • Familiarity with the gravitational constant (G) and its application
  • Basic knowledge of projectile motion and energy conservation principles
  • Ability to manipulate equations involving mass, velocity, and distance
NEXT STEPS
  • Study the derivation of gravitational potential energy equations
  • Learn about energy conservation in projectile motion
  • Explore the effects of altitude on gravitational acceleration
  • Investigate real-world applications of projectile motion in physics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and gravitational forces, as well as educators seeking to explain energy conservation in projectile motion.

Zacthor
Messages
3
Reaction score
0
An object is projected straight upward from the surface of Earth with an initial speed of 2.98 km/s. What is the maximum height it reaches?


Ok i know this seams like a really easy problem but i can't figure it out... since this question is from our chapter on gravity i have trued usuing is ke initial = potential energy final...
ke initial being(1/2 m v^2) and potential energy final being: (GMm/r^2)^1/2 M is the mass of the Earth and m is the mass of the ball
 
Physics news on Phys.org
You're not going to throw the ball so high that its distance to the center of mass of the Earth will change by a significant percentage. g is nearly constant. Therefore PE at height h will be mgh.
 
mikelepore said:
You're not going to throw the ball so high that its distance to the center of mass of the Earth will change by a significant percentage. g is nearly constant. Therefore PE at height h will be mgh.

he said 2.98 km/s. that will get you high enough for g get significantly smaller.

the potential energy for a mass at distance r from the Earth is -GmM/r, if the potential at infinity is 0, so there is both an initial and a final potential energy.
 

Similar threads

Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 38 ·
2
Replies
38
Views
4K
  • · Replies 5 ·
Replies
5
Views
14K
  • · Replies 32 ·
2
Replies
32
Views
4K
Replies
14
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K