Throwing a ball upward on top of a building, find height of building

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SUMMARY

The problem involves calculating the height of a building from which a rock is thrown upward with an initial velocity of 24 m/s and strikes the ground at a velocity of 43 m/s. The acceleration due to gravity is 9.8 m/s². The solution requires using the equations of motion to first determine the time of flight and then the displacement, ultimately leading to the building's height. It is confirmed that solving a quadratic equation is unnecessary for this problem.

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  • Understanding of kinematic equations of motion
  • Knowledge of initial and final velocity concepts
  • Familiarity with acceleration due to gravity
  • Ability to perform basic algebraic manipulations
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  • Study the kinematic equations for uniformly accelerated motion
  • Learn how to derive displacement from initial velocity and time
  • Explore examples of projectile motion problems
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Homework Statement


Please help me with this problem:
Rock is thrown straight up with a velocity of 24 m/s from the edge of a building. The rock is moving at 43 m/s when it strikes the ground. Acceleration is 9.8 m/s^2. How tall is the building?



I know it involves the equations of motion. I think the first step is solving for the time with the quadriatic eq.

Homework Equations




The Attempt at a Solution

 
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Figure out the time, then the displacement. Two different equations. You don't need to solve a quadratic equation.
 

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