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Throwing a frisbee and measuring change in mechanical energy

  1. Nov 10, 2012 #1
    A 75g Frisbee I thrown from a point 1.1 m above the ground with a speed 12 m/s when it has reached a height $.1 m its speed is 10.5 m/s What is the reduction in Emec of the frisbee-earth system because of air drag?


    At first I thought Since ΔEmec= Δk+Δu the change is -0.61 J
    Then I reasoned that only the kinetic is affected by drag Δk= -1.3 J
    Now I'm wondering if I need to split the velocity into x and y components so I can separate the decrease due to gravity and the decrease due to drag? But I don't thinknthats what they want me to do. According to the guide The answer ends up being 0.53 J
     
  2. jcsd
  3. Nov 10, 2012 #2

    Doc Al

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    Staff: Mentor

    Calculate the total mechanical energy at each point.
     
  4. Nov 10, 2012 #3
    I did that too,Emec2 - Emec1 is still 0.61
     
  5. Nov 10, 2012 #4

    Doc Al

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    Staff: Mentor

    I don't see how you got that answer (or the guide's answer). What is the final height of the frisbee? Is it 0.1 m?
     
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