Tiling a 2x7 Grid with 1x1 and 1x2 Tiles: Finding the Number of Tilings

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SUMMARY

The discussion focuses on calculating the number of ways to tile a 2x7 grid using 1x1 and 1x2 tiles, referred to as singletons and doubletons. The variables defined are an, bn, and cn, representing different configurations of the tiles. The recurrence relations established are an+1 = an + bn + cn, bn+1 = 2an + bn, and cn+1 = 2an + bn + cn. These relations allow for the computation of the total number of tilings for the grid.

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\textup{A 2 x 7 rectangle has tiling with 1 x 1 and 1 x 2 tiles (singletons and doubletons).}
\textup{How many such tilings of a 2 x 7 grid are there?}

\textup{Let }a_{n}\textup{ be the number of tilings of a 2 x n grid using 1 x 1 and 1 x 2 tiles so that the}
\textup{two rightmost squares are occupied by singletons, let }b_{n}\textup{ be the number of tilings}
\textup{ with one singleton and one doubleton in the rightmost squares, and let }c_{n}\textup{ be the}
\textup{ number of other tilings (two horizontal doubletons or one vertical doubleton). The}
\textup{problem asks for }a_{7}+b_{7}+c_{7}. \textup{ When one appends another column to the right side,}
\textup{forming a 2 x (n + 1) grid, either one can add 2 singletons or a vertical doubleton, or}
\textup{one can change any singletons in the nth column to doubletons. This yields:}

a_{n+1}=a_{n}+b_{n}+c_{n}
b_{n+1}=2a_{n}+b_{n}
c_{n+1}=2a_{n}+b_{n}+c_{n}

***doubletons may be placed vertically or horizontally.

Use the recurrence relations to obtain a numerical answer to the problem.

Not sure how do start this. Any help?
 
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Consider the case where n=1. Just count the different ways you can tile the grid to figure out a1, b1, and c1.
 

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