Recurrence relations with rabbits pairs

In summary: Note: the first recurrence relation you wrote is the one for the number of babies, not of adults. For the number of adults you have to take into account the pairs that were born and have now grown up.
  • #1
jonroberts74
189
0
A single pair (male and female) of rabbits is born at the beginning of the year. Assume the following:

1) Each pair is not fertile for their first month bet thereafter give birth to four new male/female pairs at the end of every month

2) no rabbits die

a) let [tex]r_{n}[/tex] be the number of pairs of rabbits alive at the end of each month n for each integer [tex]n \ge 1[/tex] find a recurrence relation for [tex]r_{0},r_{1},r_{2}...[/tex]

b) how many rabbits will there be at the end of the yearMonth | Babies (in pairs) | Adults (in pairs) | total Pairs (r_{n})
1 |1 |0 |1
_________________________________________________________________
2 |4 |1 |5
________________________________________________________________
3 |20 |5 |25
________________________________________________________________
4 |100 |25 |125
___________________________________________________________
5 |400 |125 |525
_____________________________________________________________
6 |2100 |525 |2625
_____________________________________________________________
7 |10500 |2625 |13125
______________________________________________________________
8 |52500 |13125 |65625
_______________________________________________________________
9 |262500 |65625 |328125
________________________________________________________________
10 |1312500 |328125 |1640625
_________________________________________________________________
11 |6562500 |1640625 |8203125
_________________________________________________________________
12 |328125000 |8203125 |41015625

(sorry for the ugly table)

the recurrence relation seems to be [tex]r_{n} = a+4a[/tex] where a = number of adults, for [tex]n \ge 1[/tex]

is that correct?

and part b) would be 41,015,625 pairs so 82,031,250 rabbits
 
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  • #2
jonroberts74 said:
the recurrence relation seems to be [tex]r_{n} = a+4a[/tex] where a = number of adults, for [tex]n \ge 1[/tex]

is that correct?

It is not correct. You have now counted the adults and the newborns, but not the rabbits which are now 1 month old.



It is also not in the form they are looking for. You have to express ##r_n## in terms of ##r_k## with ##k<n##. So for example, a possible (but obviously incorrect) answer would be ##r_n = 100r_{n-1} + 5\sqrt{r_{n-3}r_{n-2}}##.

You express it in terms of ##a##. Can you perhaps express ##a## in terms of ##r_k##?
 
  • #3
micromass said:
It is not correct. You have now counted the adults and the newborns, but not the rabbits which are now 1 month old.
It is also not in the form they are looking for. You have to express ##r_n## in terms of ##r_k## with ##k<n##. So for example, a possible (but obviously incorrect) answer would be ##r_n = 100r_{n-1} + 5\sqrt{r_{n-3}r_{n-2}}##.

You express it in terms of ##a##. Can you perhaps express ##a## in terms of ##r_k##?

aren't the rabbits that are 1 month old adults now because it says they are not fertile for the first month then give birth to 4 (male/female) pairs at the end of the month.

or am I incorrect in my computation

should it be

in the beginning theres

1 pair born, then the first month they have no births then the second month they make 4 pairs.

then the 3rd month: the original pair breeds 4 , the 4 pairs from the last month grow to maturity for a total of 9 pairs

then in month 4 there's 5 pairs that can breed, 4 pairs that mature, and 20 pairs born
 
Last edited:
  • #4
adult pairs = adults of previous month + maturing pairs of previous month

maturing pairs = baby pairs from previous month

baby pairs = 4(adult pairs from previous month + maturing pairs from previous month)
 
Last edited:
  • #5
| month | Adults | babies | maturing | total |
| ----- | ------ | ------ | --------- | ----- |
| 1 | 0 | 0 | 1 | 1 |
| 2 | 1 | 4 | 0 | 5 |
| 3 | 1 | 4 | 4 | 9 |
| 4 | 5 | 20 | 4 | 29 |
| 5 | 9 | 36 | 20 | 65 |
| 6 | 29 | 116 | 36 | 181 |
| 7 | 65 | 260 | 116 | 441 |
| 8 | 181 | 724 | 260 | 1165 |
| 9 | 441 | 1764 | 724 | 2929 |
| 10 | 1165 | 4660 | 1765 | 7589 |
| 11 | 2929 | 11716 | 4660 | 19305 |
| 12 | 7589 | 30356 | 11716 | 49661 |
 
Last edited:
  • #6
jonroberts74 said:
| month | Adults | babies | maturing | total |
| ----- | ------ | ------ | --------- | ----- |
| 1 | 0 | 0 | 1 | 1 |
| 2 | 1 | 4 | 0 | 5 |
| 3 | 1 | 4 | 4 | 9 |
| 4 | 5 | 20 | 4 | 29 |
| 5 | 9 | 36 | 20 | 65 |
| 6 | 29 | 116 | 36 | 181 |
| 7 | 65 | 260 | 116 | 441 |
| 8 | 181 | 724 | 260 | 1165 |
| 9 | 441 | 1764 | 724 | 2929 |
| 10 | 1165 | 4660 | 1765 | 7589 |
| 11 | 2929 | 11716 | 4660 | 19305 |
| 12 | 7589 | 30356 | 11716 | 49661 |

Your table seems correct to me (I haven't checked it to the end)


jonroberts74 said:
the recurrence relation seems to be [tex]r_{n} = a+4a[/tex] where a = number of adults

Try to avoid using "a" (the number of adults), it's unnecessary.

How could you write it in terms of [itex]r_n[/itex]? What do all the adult rabbits have in common?
 
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  • #7
I think the recurrence relation is

[tex]r_{n}=r_{n-2}+4r_{n-2} + r_{n-1} - r_{n-2} [/tex]

which simplifies to

[tex] 4r_{n-2} + r_{n-1}[/tex]
 
  • #8
jonroberts74 said:
which simplifies to

[tex] 4r_{n-2} + r_{n-1}[/tex]

Looks good to me!
 
  • #9
jonroberts74 said:
I think the recurrence relation is

[tex]r_{n}=r_{n-2}+4r_{n-2} + r_{n-1} - r_{n-2} [/tex]

which simplifies to

[tex] 4r_{n-2} + r_{n-1}[/tex]

Seems ok!
 

1. How do you define a recurrence relation with rabbits pairs?

A recurrence relation with rabbits pairs is a mathematical equation that describes the growth of a population of rabbits over time. It is typically expressed in terms of the number of pairs of rabbits in a given generation, and the number of pairs in the previous generation.

2. What is the significance of rabbits in the context of recurrence relations?

Rabbits are often used as an example in recurrence relations because they have a well-defined breeding pattern that can be easily represented mathematically. This allows for a simple and intuitive understanding of the concept of recurrence relations.

3. How do you solve a recurrence relation with rabbits pairs?

To solve a recurrence relation with rabbits pairs, you can use a technique called the "Fibonacci sequence". This involves starting with a base case (such as the number of pairs in the first generation) and using the recurrence relation to calculate the number of pairs in subsequent generations.

4. Can recurrence relations with rabbits pairs be applied to other populations?

Yes, recurrence relations can be applied to any population that follows a pattern of growth over time. This could include other animals, plants, or even human populations.

5. What real-world applications do recurrence relations with rabbits pairs have?

Recurrence relations with rabbits pairs can have practical applications in fields such as biology, ecology, and economics. They can be used to model and predict the growth of populations, which can be useful for understanding and managing natural resources and predicting market trends.

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