Undergrad Tiling Polygons: Can Any n-Sided Polygon Tile?

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The discussion centers on whether any n-sided polygon can be manipulated to tile with similar polygons, specifically questioning the possibility for 20-sided or 53-sided shapes. An article is referenced that explores tiling with pentagons, suggesting that some junctions in the tiling can be viewed as hexagons due to collinear sides. It is noted that a plane tiling must have an average vertex degree of at most 6, which limits the ability to manipulate polygons with more than six sides into a configuration that appears to have fewer. The conversation seeks an intuitive proof regarding the tiling capabilities of various polygons. Ultimately, the complexities of polygon tiling raise intriguing mathematical challenges.
thetexan
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Here is an interesting article...

http://discovermagazine.com/2016/janfeb/55-pentagon-puzzler

This raises the question...can any polygon with n sides be manipulated so that it will tile with other similar polygons? Can one find a shape of a 20 sided polygon that will tile with the same shaped 20 sided polygon, or a 53 sided polygon?

More to the point...is there any intuitive proof one way or the other?

tex
 
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thetexan said:
Here is an interesting article...

http://discovermagazine.com/2016/janfeb/55-pentagon-puzzler

This raises the question...can any polygon with n sides be manipulated so that it will tile with other similar polygons? Can one find a shape of a 20 sided polygon that will tile with the same shaped 20 sided polygon, or a 53 sided polygon?

More to the point...is there any intuitive proof one way or the other?

tex
Notice that some junctions are part way along a side of one of the pentagons involved. This means that from a graph-theoretical view these are hexagons. They appear as pentagons in the geometric view because two consecutive sides are collinear.
A plane tiling must have average degree at most 6, counting every junction as a vertex. The pentagons can be made to look like regular degree 6 by subdividing a side, but there is no way to make a polygon with more than 6 sides look to have fewer.
 

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