Time-averaged potential of hydrogen

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cscott
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Homework Statement



The time-averaged potential of a neutral hydrogen atom is given by

[tex]V = \frac{q}{4 \pi \epsilon_0} \frac{e^{-\alpha r}}{r} \left ( 1 + \frac{\alpha r}{2} \right )[/tex]

[tex]\alpha = 2/a_0[/itex], where [itex]a_0[/itex] is the Bohr radius.<br /> <br /> Find the charge distribution (continuous and discrete) which will give you this potential.<br /> <br /> <h2>The Attempt at a Solution</h2><br /> <br /> Totally stuck here except I think the charge density of the |1s> state should be<br /> <br /> [tex]\rho = e<1s|1s>[/itex],<br /> <br /> however that doesn't get me very far. Is the second term in V the contribution of the proton?[/tex][/tex]
 
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There's no need to think about quantum mechanics here. This is just a classical electromagnetics problem. You have a potential. Find the corresponding electric field and then take its divergence to find the charge density.