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Time dilation around a planet.

  1. Sep 18, 2012 #1
    If I wanted to figure out the gravitational time dilation at different points in a the field around earth, could I just use v=gt. and find the speed that I would be moving if I went into free-fall from point x to point y. To figure out the time difference between x and y?
    and the t in v=gt would be the time in my free-fall frame. Then once I knew v , I could use the standard time dilation equation from SR.
     
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  3. Sep 18, 2012 #2

    A.T.

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    No. Gravitational time dilation is different from movement time dilation. Here is the formula:
    http://en.wikipedia.org/wiki/Gravitational_time_dilation#Outside_a_non-rotating_sphere
     
  4. Sep 18, 2012 #3
    I understand that its different Im just wondering why I cant use this math approach to figure out the time dilation between these 2 frames.
     
  5. Sep 18, 2012 #4

    PAllen

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    Because both curvature and motion contribute to clock difference between a source and receiver. Imagine a receiver on hovering high above earth. Imagine a bunch of clocks at some place on earth: sitting on the ground, thrown upwards, kicked sidway, etc. The receiver will see a different rate for each of the source clocks, influenced by their difference in motion and by the curvature of spacetime between them and the receiver.

    In a situation like this (essentially static gravity), we call the difference observed for the clock sitting on the ground gravitational time dilation. Then the different clocks moving relative to this can be analyzed as an additional motion effect.

    There is a way to treat all the cases in a uniform way a as a function of source and target world line and the intervening geometry. However, I don't know if you have the background for it: do you know what parallel transport of 4-vectors in curved spacetime is?
     
  6. Sep 19, 2012 #5
    ok thanks for your response. In my scenario I wasn't trying to figure out the time dilation for a moving observer in a G field. I was just wondering if I Could find the speed one would be at if he was in free-fall until he got to the other point, And use that speed to find the time dilation using SR equations. Is there a way to figure out how much light would be red shifted from one frame to another. And these frames are stationary in the gravitational field. Then once I knew how much the light was red shifted I could figure out what speed an observer would need to move to cancel the redshift and use this v in the SR equation to figure out the time dilation in the Gravitational field. Im not saying the observers are moving, im just using this as a way to figure out the effect.
     
  7. Sep 19, 2012 #6

    PAllen

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    If you want to use something from SR for gravitational time dilation, what you should use is SR doppler rather than SR time dilation. Then, the parallel transport method I alluded to applies - if you compute the tangent vector (4-velocity) of a ground stationary observer, and parallel transport along a light path (null geodesic) to a higher stationary observer world line, you find the two vectors (transported tangent; and tangent of higher observer world line) are not parallel, implying a local relative motion that is equivalent to the gravitational effect. Then, if you apply the SR doppler formula, using this local relative velocity of the source along with the local light propagation vector, you would get a correct figure for gravitational redshift (= what is called gravitational time dilation).
     
  8. Sep 19, 2012 #7
    Actually, if you start with a scalar speed v of a particle as measured by a local static observer at r and freefall, regardless of the path, to radius s with resulting locally measured scalar speed u, the ratio of the kinetic time dilations will equal the ratio of the gravitational time dilations, so that

    sqrt(1 - (v/c)^2) / sqrt(1 - (u/c)^2) = sqrt(1 - 2 m / r) / sqrt(1 - 2 m / s)

    This comes from conservation of energy, whereby the quantity E_r z_r = m c^2 sqrt(1 - 2 m / r) / sqrt(1 - (v/c)^2) is conserved for a particular freefalling particle, where z_r is the local gravitational time dilation. The same is true for frequencies of light, although massless, giving E_r z_r = h f_r z_r. So the smaller the gravitational time dilation, the greater the locally measured frequency of light.
     
    Last edited: Sep 19, 2012
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