Time dilation spacecraft travel problem

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SUMMARY

The discussion centers on calculating the speed required for a spacecraft to experience time dilation such that one day on Earth corresponds to two days on the spacecraft. The relevant equation used is t = t(0) / (sqrt(1 - v^2/c^2)), where proper time is defined as the time measured by a clock at rest relative to the events being observed. The proper time is set at 86400 seconds (1 day), while the time experienced on the spacecraft is 172800 seconds (2 days). The solution confirms that the time on the spacecraft is indeed the proper time.

PREREQUISITES
  • Understanding of time dilation concepts in physics
  • Familiarity with the equation t = t(0) / (sqrt(1 - v^2/c^2))
  • Basic knowledge of proper time and its significance in relativity
  • Concept of relative velocity in the context of special relativity
NEXT STEPS
  • Research the implications of time dilation in special relativity
  • Explore the Lorentz transformation equations
  • Learn about the effects of velocity on time perception in high-speed travel
  • Investigate real-world applications of time dilation in spacecraft design
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Physicists, aerospace engineers, and anyone interested in the effects of relativistic speeds on time perception and spacecraft travel.

Benzoate
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Problem: How fast must a spacecraft travel relative to the Earth for each day on the Earth to correspond to 2 days on the earth?

My solution:

proper time = 1 day = 86400 seconds
time on space craft= 2 days= 172800 seconds
relavant equation: t=t(0)/(sqrt(1-v^2/c^2)

I would plug in both the proper time and relative time into time dilation equation in order to find the speed of the spacecraft correct?
 
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The time on the spacecraft would be the proper time. Other than this you are correct.

The proper time is the time between events measure by a clock that is present and at rest at both events. Here, the events are the two points mentioned in the spacecraft 's journey. The only clock present and at rest at both of these events is the one on the ship.
 

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