Time given angular velocity/displacement

  • Thread starter mcarloni
  • Start date
  • #1
5
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A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 2.90 to 5.40 rev/s while rotating through one half of a revolution. How much time does this maneuver take?

Knowns:
w0 = 2.9 rev/sec * 2pi rad = 18.22 rad/sec
w = 5.4 rev/sec * 2pi rad = 33.92 rad/sec
θ = 180?

θ = 1/2 (w0 + w) t
180 = 1/2 (18.22 + 33.92) t
180 = 1/2 (52.14) t
(/180) 180 t = 26.07 (/180)
t = .1448

I know this is incorrect, and would appreciate help in the right direction.
 

Answers and Replies

  • #2
gneill
Mentor
20,913
2,862
Don't mix radians and degrees!
 
  • #3
5
0
Got it! :D

θ = 180 deg *(pi/180) = 3.14 rad

ω = 26.07

θ = ωt

which turns into

t = θ/ω

t = .12044
 

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