Time independent Schrödinger Eqn in a harmonic potential

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SUMMARY

The discussion focuses on solving the time-independent Schrödinger equation for a harmonic oscillator using the series method. The equation is given as $$-\frac{\hbar^{2}}{2m}\frac{\mathrm{d}^2 \psi }{\mathrm{d} x^2}+\frac{1}{2}m\omega ^{2}x^2\psi =E\psi $$, with substitutions $$\xi \equiv \sqrt{\frac{m\omega }{\hbar}}x$$ and $$K\equiv \frac{2E}{\hbar\omega }$$ leading to the simplified form $$\frac{\mathrm{d} ^2\psi }{\mathrm{d} \xi ^2}=\left ( \xi ^2-K \right )\psi $$.

To derive the final equation, it is essential to apply the chain rule for derivatives, specifically using $$\frac{d}{dx} = \frac{d\xi}{dx} \frac{d}{d\xi}$$ to account for the change of variables correctly.

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  • Knowledge of dimensionless variable substitutions
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  • Study the derivation of the time-independent Schrödinger equation for various potentials
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Homework Statement


I am currently reading a textbook on solving the Schrödinger equation for the harmonic oscillator using the series method;
$$-\frac{\hbar^{2}}{2m}\frac{\mathrm{d}^2 \psi }{\mathrm{d} x^2}+\frac{1}{2}m\omega ^{2}x^2\psi =E\psi $$

It starts by using these two dimensionless variable substitutions (which I gather is standard practise): $$\xi \equiv \sqrt{\frac{m\omega }{\hbar}}x$$and$$K\equiv \frac{2E}{\hbar\omega }$$
to produce the simplified equation: $$\frac{\mathrm{d} ^2\psi }{\mathrm{d} \xi ^2}=\left ( \xi ^2-K \right )\psi $$

I cannot match the final equation using these substitutions alone. Surely there must be some adjustment for the change of variables in the derivative? Please can someone explain how to get the final (simplified) equation? (I am a newcomer to quantum mechanics!)

Thanks in advance.
 
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You need to use the chain rule: ##\frac{d}{dx} = \frac{d\xi}{dx} \frac{d}{d\xi}##.
 

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