Consider a string of total length L, made up of three segments of equal length. The mass per unit length of the first segment is mu, that of the second is 2*mu, and that of the third mu/4. The third segment is tied to a wall, and the string is stretched by a force of magnitude T_s applied to the first segment; T_s is much greater than the total weight of the string.
Express the time t in terms of L, mu, and T_s. I must use those variables for this answer, no values were given for those variables so they must be included in the answer.
Velocity=sqrt(T_s/mu) -velocity of string
where, T_s is the tension of the string and mu is its linear denisty. mu=mass/length
The Attempt at a Solution
since, time=v/m ==> m/s/m = seconds right? Edit: = 1/seconds
How I got that:
By pulling out the number multiplied by mu from the sqaure root I get:
The first segment is a velocity of 1*sqrt(T_s/mu)
The second segment is a velocity of 1/sqrt(2)*sqrt(T_s/mu)
The third segment is a velocity of 2*sqrt(T_s/mu)
Add those velocities toegther. Then to get the time you can just divide the velocity by the length of the string that is divided into three equal segments. So, dividing by (L/3) will give the answer. Anyone see what is wrong with my answer?