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## Homework Statement

A 1203.0 kg weather rocket is launched straight up. The rocket motor provides a constant acceleration for 11.2 s, then the motor stops. The rocket altitude 24.1 s after launch is 2023.0 m. You can ignore any effects of air resistance. What was the rocket's acceleration during the first 11.2 s? What is the rocket's velocity as it passes through a cloud 2023.0 m above the ground?

## Homework Equations

(a)d=Vit + 1/2 at^2...

(b) Vf= Vi + at...

(c) d= di + Vf (t) - 1/2 at^2

## The Attempt at a Solution

So I used the first equation to findthe distance the rocket traveled in the first 11.2 seconds and subtract that with altitude given...and know that the starting speed is 0m/s i tried to determine the speed using vfinal {throughout the first 2 eqns. i used a= -9.80 m/s^2}and then plugged it into the last equation to determine the acceleration..im gettin the wrong answer ..pls help