To which of the two cubes has a larger moment of inertia?

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SUMMARY

The discussion centers on determining which of two cubes has a larger moment of inertia. Participants agree that the cube on the right has a larger moment of inertia due to its rotation not being around the principal axes that pass through the center of mass. The relevant equation for calculating moment of inertia is highlighted, emphasizing that it can be derived from the parallel axis theorem, although some participants suggest avoiding its use in this context. Calculating the moment of inertia tensor is recommended for deeper understanding.

PREREQUISITES
  • Understanding of moment of inertia and its significance in rotational dynamics
  • Familiarity with the parallel axis theorem and its applications
  • Knowledge of integral calculus for evaluating moment of inertia
  • Basic concepts of principal axes and their relation to mass distribution
NEXT STEPS
  • Calculate the moment of inertia for both cubes using the standard definition
  • Explore the moment of inertia tensor for various shapes
  • Learn about the implications of the parallel axis theorem in different scenarios
  • Investigate the moment of inertia for a flat rectangular sheet in both straight and diagonal orientations
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Students and professionals in physics, mechanical engineering, and materials science who are studying rotational dynamics and moment of inertia calculations.

Cosmossos
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To which of the two cubes has a larger moment of inertia?
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I think it's the right one, is it correct?
How can I explain that without using the parallel axis theorem?
 
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Cosmossos said:
To which of the two cubes has a larger moment of inertia?
View attachment 23012
I think it's the right one, is it correct?
How can I explain that without using the parallel axis theorem?

Why do you say the right one? Are you familiar with the relevant equation for calculating the moment of inertia?
 
what relevant equation?

I think it's the right one because We know that the minimal moment of inertia is throw the principal axes that goes throw the center of mass. in the right one , the rotation isn't throw the principal axes . there is also the following theorem :

The moment of inertia about an arbitrary axis is equal to the
moment of inertia about a parallel axis passing through the
center of mass plus the moment of inertia of the body about
the arbitrary axis, taken as if all of the mass M of the body
were at the center of mass.

Am I wrong?
 
Last edited:
Cosmossos said:
what relevant equation?

I think it's the right one because We know that the minimal moment of inertia is throw the principal axes that goes throw the center of mass. in the right one , the rotation isn't throw the principal axes . there is also the following theorem :

The moment of inertia about an arbitrary axis is equal to the
moment of inertia about a parallel axis passing through the
center of mass plus the moment of inertia of the body about
the arbitrary axis, taken as if all of the mass M of the body
were at the center of mass.

Am I wrong?

There may be a shortcut way to tell which has a higher moment of inertia, but for me, I'd need to calculate it. I'd use the standard definition of the Mmoment of inertia, and evaluate thge integral for the diagonal case. I don't think you can use the parallel axis theorem, since the two axes are not parallel.

I'd do the 2-D case first, to see if it offered some intuition. That is, the moment of inertia for a flat rectangular sheet, with the axes going straight versus diagonal.
 
I think they'll turn out to be equal. Try computing the moment of inertia tensor.
 

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