To which of the two cubes has a larger moment of inertia?

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Homework Help Overview

The discussion revolves around determining which of two cubes has a larger moment of inertia, exploring the principles of rotational dynamics and the relevant equations involved in calculating moment of inertia.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss their reasoning for selecting one cube over the other based on the orientation of the axes of rotation and the properties of moment of inertia. Questions arise regarding the relevant equations and the application of the parallel axis theorem.

Discussion Status

There is an ongoing exploration of different perspectives on the moment of inertia of the cubes. Some participants suggest calculating the moment of inertia tensor, while others express uncertainty about the application of certain theorems. No consensus has been reached yet.

Contextual Notes

Participants are navigating the constraints of not using the parallel axis theorem and are considering the implications of calculating moment of inertia for different axes of rotation. There is mention of needing to compute values to draw conclusions.

Cosmossos
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To which of the two cubes has a larger moment of inertia?
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I think it's the right one, is it correct?
How can I explain that without using the parallel axis theorem?
 
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Cosmossos said:
To which of the two cubes has a larger moment of inertia?
View attachment 23012
I think it's the right one, is it correct?
How can I explain that without using the parallel axis theorem?

Why do you say the right one? Are you familiar with the relevant equation for calculating the moment of inertia?
 
what relevant equation?

I think it's the right one because We know that the minimal moment of inertia is throw the principal axes that goes throw the center of mass. in the right one , the rotation isn't throw the principal axes . there is also the following theorem :

The moment of inertia about an arbitrary axis is equal to the
moment of inertia about a parallel axis passing through the
center of mass plus the moment of inertia of the body about
the arbitrary axis, taken as if all of the mass M of the body
were at the center of mass.

Am I wrong?
 
Last edited:
Cosmossos said:
what relevant equation?

I think it's the right one because We know that the minimal moment of inertia is throw the principal axes that goes throw the center of mass. in the right one , the rotation isn't throw the principal axes . there is also the following theorem :

The moment of inertia about an arbitrary axis is equal to the
moment of inertia about a parallel axis passing through the
center of mass plus the moment of inertia of the body about
the arbitrary axis, taken as if all of the mass M of the body
were at the center of mass.

Am I wrong?

There may be a shortcut way to tell which has a higher moment of inertia, but for me, I'd need to calculate it. I'd use the standard definition of the Mmoment of inertia, and evaluate thge integral for the diagonal case. I don't think you can use the parallel axis theorem, since the two axes are not parallel.

I'd do the 2-D case first, to see if it offered some intuition. That is, the moment of inertia for a flat rectangular sheet, with the axes going straight versus diagonal.
 
I think they'll turn out to be equal. Try computing the moment of inertia tensor.
 

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