Topology Problem: Closure X Path-Connected?

  • Thread starter Thread starter mveritas
  • Start date Start date
  • Tags Tags
    Topology
Click For Summary
SUMMARY

The discussion centers on the relationship between path-connected spaces and their closures in topology. It is established that while a path-connected space X may intuitively suggest that its closure is also path-connected, this is not necessarily true. A key counterexample provided is the set {(x, sin(1/x)) | x ∈ ]0,1]} in ℝ², which is path-connected, but its closure is not. This example is frequently encountered in topology exams and serves as a critical reminder of the nuances in connectedness properties.

PREREQUISITES
  • Understanding of path-connected spaces in topology
  • Familiarity with closure of sets in topological spaces
  • Knowledge of counterexamples in mathematical proofs
  • Basic concepts of connectedness properties in topology
NEXT STEPS
  • Study the properties of closure in topological spaces
  • Explore various examples of path-connected and non-path-connected spaces
  • Learn about the implications of connectedness in higher-dimensional spaces
  • Investigate the significance of the sine curve as a counterexample in topology
USEFUL FOR

Mathematics students, particularly those studying topology, educators preparing for exams, and anyone interested in the intricacies of connectedness properties in mathematical spaces.

mveritas
Messages
5
Reaction score
0
Hello, I have a question about topology.

If X is a path-connected space then is it also true that closure X is path-connected?

I think it's obvious, but I can't solve it clearly...
 
Physics news on Phys.org
Ah, this is a very good question. In fact, this very question was asked on my topology exam...

It is maybe obvious to you (and to me), but it is false. Consider

\{(x,\sin(1/x))~\vert~x\in ]0,1]\}\subseteq \mathbb{R}^2

This is clearly a path connected set. However, it's closure is not path connected.

I suggest that you remember this example very well. Because it is a very frequent counterexample to all sort of connectedness-properties. And it's a popular exam question as well :smile:
 
micromass said:
Ah, this is a very good question. In fact, this very question was asked on my topology exam...

It is maybe obvious to you (and to me), but it is false. Consider

\{(x,\sin(1/x))~\vert~x\in ]0,1]\}\subseteq \mathbb{R}^2

This is clearly a path connected set. However, it's closure is not path connected.

I suggest that you remember this example very well. Because it is a very frequent counterexample to all sort of connectedness-properties. And it's a popular exam question as well :smile:

-----------------------------------------------

Thank you!
 
It is used so often that it even has a (rather dull) name: the sine curve[/url].
 
Last edited by a moderator:

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K