Topology (specifically homotopy) question

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Discussion Overview

The discussion revolves around a topology question related to homotopy, specifically addressing two parts: proving that every map from a space X to R^n is homotopic to a constant map, and showing that a non-surjective map from X to S^n is also homotopic to a constant map. The context is academic, as it pertains to a past exam paper without provided solutions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant requests assistance with proving that every map e: X-> R^n is homotopic to a constant map.
  • Another participant suggests finding a homotopy H: I x X --> R^n that connects e to the constant map sending everything in X to 0.
  • A different participant notes that R^n is contractible, providing a visualization by suggesting sending points to the origin along straight lines.
  • One participant observes that the two parts of the question are essentially the same.

Areas of Agreement / Disagreement

Participants have not reached a consensus, and multiple viewpoints on how to approach the problem are presented.

Contextual Notes

The discussion does not clarify specific assumptions or definitions that may be necessary for the proofs, nor does it resolve any mathematical steps involved in the arguments.

timboj2008
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Could anybody help me with this topology question?

i) Prove that every map e: X-> R^n is homotopic to a constant map.

ii) If f: X->S^n is a map that is not onto (surjective), show that f is homtopic to a constant map.

It's part of a past exam paper but it does not come with solutions. Any help on the solution would be greatly appreciated.

Thanks.
 
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i) Try to find a homotopy H:I x X-->R^n between e and the map that sends everything in X to 0.

ii) Hint: Use (i)
 
Basically you need to realize that R^n is contractible. This is pretty easy to visualize: e.g. take R^2 or R^3 and send every point to the origin along the straight line between them.
 
these are the same question.
 

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