Torque calculations for peristaltic pump

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SUMMARY

The discussion centers on calculating the torque required to operate a peristaltic pump at 26 revolutions per minute (rev/min) using a gear arrangement with a 13.1:1 ratio. The user determined an input speed of 340 rev/min is necessary to achieve the desired output speed. Key calculations involve the pump's torque, which can be derived from the formula: pump torque = ((pressure * displacement)/2π) * efficiency. For example, with a pressure of 240 bar and a displacement of 55 cc, the calculated torque is 200 Nm.

PREREQUISITES
  • Understanding of gear ratios and their impact on rotational speed
  • Knowledge of torque calculations, including the relationship between pressure, displacement, and efficiency
  • Familiarity with measuring devices such as spring scales for force measurement
  • Basic principles of peristaltic pump operation and performance metrics
NEXT STEPS
  • Research the calculation of torque for various pump types using pressure and displacement
  • Learn about gear ratio calculations and their implications for input and output speeds
  • Explore the use of pitch circle diameter in gear design and torque calculations
  • Investigate the selection of gear modules for multi-stage gearboxes to achieve desired ratios
USEFUL FOR

Mechanical engineers, pump system designers, and technicians involved in the design and operation of peristaltic pumps and gear systems.

karl8695
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Hi all,

I have a peristaltic pump that i need to rotate at 26 rev/min. The gear arrangement attached to the pump is calculated at 13.1:1 therefore I am assuming an input speed of 340rev/min is required to produce a reduction in speed to the desired output of 26 rev/min.

Gear A (1st driver) - 12 teeth
Gear B (1st driven) - 43 teeth
Gear C (2nd driver) - 9 teeth
Gear D (2nd driven) - 33 teeth

My problem is that I need to know what Force is required to turn my pump and thus the the force required by my drive unit, a 'power spring' to transmit the desired force. I do not have any measuring devices other that a spring scale graduated in Kg. I did however determine the force required to rortate the input shaft, albeit not at the correct speed which came out at an average of 1.8 Kg over 10 tests. I did this by tying a thread around the input shaft to the gear arrangement and then attaching the other end to the spring scale and simply pulling and recording the max pull in Kg over 10 separate attempts.

Can I determine the torque (power) i need from my power spring to turn my pump at a constant speed of 26 rev/min?

Thanks in advance
 
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Some random thoughts:
If the ratio of your gears is 13.1:1 I would have thought the other way. That you only need 2rpm input to get 26 rpm from the pump.

I think to measure the torque you should offer the pitch of the gears or the pitch circle diameter/radius of the gears.

Input torque on the gears should be (torque of pump)/13.1
I think you need to provide the displacement of the pump.

pump torque = ((pressure * displacement)/2pi)* efficiency

eg: pressure = 240 bar
displacement = 55cc
eff = 0.95

T= 200Nm
 
No, the pump definatley works with a geared reduction so 340 rev/min input speed.
Displacement of the pump = 0.3Litres/min
Pressure = 0.1 bar
Efficience is unknown
 
Hey don't know whom to ask but i have a question...
I am using a gear box and its center distances are 70,90 and 120...its a three stage reduction gear box... i want a total gearbox ratio of 40...how should i select the modules i have to use in each 3 stages for getting proper ratio ?
 

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