What is the torque exerted by the flywheel on the machine?

Click For Summary
SUMMARY

The discussion focuses on calculating the torque exerted by a flywheel on a machine, specifically a flywheel with a diameter of 2.0 m and a mass of 260 kg, achieving a maximum angular velocity of 1400 rpm. The average power delivered to the machine is calculated to be approximately 279,400 W. The torque is derived using the formula τ = P/ω, resulting in a value of 1905.9 N*m, which is rounded to 1900 N*m for significant figures. The conversation highlights the importance of understanding the changing angular velocity due to energy loss during operation.

PREREQUISITES
  • Understanding of angular velocity and its conversion from rpm to rad/s
  • Familiarity with the concept of power in rotational systems
  • Knowledge of torque and its relationship to power and angular velocity
  • Basic principles of energy conservation in mechanical systems
NEXT STEPS
  • Study the principles of rotational dynamics and energy conservation
  • Learn about the relationship between torque, power, and angular velocity in mechanical systems
  • Explore advanced topics in flywheel energy storage systems
  • Investigate the effects of variable angular velocity on torque calculations
USEFUL FOR

Mechanical engineers, physics students, and professionals involved in energy storage systems or rotational mechanics will benefit from this discussion.

traviata
Messages
8
Reaction score
2

Homework Statement



Flywheels are large, massive wheels used to store energy. They can be spun up slowly, then the wheel's energy can be released quickly to accomplish a task that demands high power. An industrial flywheel has a 2.0 m diameter and a mass of 260 kg . Its maximum angular velocity is 1400 rpm .
  1. The flywheel is disconnected from the motor and connected to a machine to which it will deliver energy. Half the energy stored in the flywheel is delivered in 2.5 s . What is the average power delivered to the machine?
  2. How much torque does the flywheel exert on the machine?

Homework Equations



P=τ⋅ω

The Attempt at a Solution



From working out earlier parts of the problem, I already have:

ω=1400rpm*(min/60s)*(2π rad/rev) = 146.61 rad/s
P = ΔE/Δt = ½Kmax/Δt = 1/8*m(ωr)2/Δt = 1/8*(260kg)*(146.61rad/s*1.0m)2 = 2.794*105 W

Mastering Physics marks this as correct. However, when I solve for torque in terms of power and angular velocity

τ = P/ω = 2.794*105 W / 146.61 rad/s = 1905.9 N*m

Master Physics marks 1900 N*m (it requires 2 significant figures), as incorrect. Any suggestions?
 
Physics news on Phys.org
traviata said:
τ = P/ω
Will ω be constant?
 
ω is not constant, as the kinetic energy of the flywheel changes.
 
traviata said:
ω is not constant, as the kinetic energy of the flywheel changes.
So what value can you use in P/ω?
 
Are you saying I can't use ω because it's not constant. Is there another equation I have to use?
 
traviata said:
Are you saying I can't use ω because it's not constant. Is there another equation I have to use?
Rotational systems such as this are highly analogous to linear systems.
If you had a moving mass that loses half its (known) KE in a known time under constant force, could you find that force?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 10 ·
Replies
10
Views
15K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
1
Views
6K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 9 ·
Replies
9
Views
10K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 5 ·
Replies
5
Views
20K