Solve Flywheel & Torque Homework: Find Torque

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SUMMARY

The discussion focuses on calculating the torque exerted by an industrial flywheel with a diameter of 1.5 m and a mass of 270 kg, operating at a maximum angular velocity of 1500 rpm. The user attempted to find the torque using the equations for rotational kinetic energy and torque, but concluded that the flywheel, turning at a constant speed, exerts no torque without angular acceleration. The correct approach requires understanding that torque is only present when there is a change in angular velocity.

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Homework Statement


Flywheels are large, massive wheels used to store energy. They can be spun up slowly, then the wheel's energy can be released quickly to accomplish a task that demands high power. An industrial flywheel has a 1.5 m diameter and a mass of 270 kg. Its maximum angular velocity is 1500 rpm. How much torque does the flywheel exert on the machine?


Homework Equations


to find Wf I used (1/2 K ) = 1/2 I wf ^ 2

then Wf=Wo+alpha(t)

then T for torque=I alpha

The Attempt at a Solution



to find Wf I used (1/2 K ) = 1/2 I wf ^ 2

=(1/2 (9.4*10^5 (this is what the amount of energy stored) = 1/2 (70.3125) <--This number is I=1/2mr^2 (wf^2)

I rearranged this to find Wf
Wf^2= .5(9.4*10^5) / .5 (70.3125)

wf= sqrt 470,000 / 35.15
= sqrt 13371.26
wf = 115.63

then i used wf=wo+alphat to find the angular acceleration
alpha=wf / wo + t
alpha=115.63 / 157 rad/s+2.1 s
alpha = .7267

then torque=I alpha
=70.3125 (.7267)
T=51.09 N*M

It was wrong and I have no idea what I'm doing wrong
 
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The flywheel is turning at a constant speed. How much energy does the flywheel have in this condition?
 
The problem needs to indicate some rate of angular acceleration or deceleration such as change in angular velocity over some period of time, otherwise, if there's no change in angular velocity, then as SteamKing mentioned, there's no torque.
 

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