The discussion revolves around determining the force (torque) required to throw a mass using a system of two pulleys and a belt, specifically in the context of a snowblower. Participants explore the necessary calculations involving density, mass, power, and the mechanics of the system.
Participants generally agree on the need to clarify definitions and parameters for the calculations, but multiple competing views remain regarding the best approach to determine the necessary torque and power for the snowblower system. The discussion remains unresolved regarding the specific calculations and equipment adjustments needed.
Limitations include the need for precise definitions of terms like "throw," the dependence on specific measurements for the snowblower setup, and unresolved calculations regarding mass and force.
anorlunda said:500kg/m(3) is a density, not a mass, not a force.
There is not a single formula, but a collection of formulas. See https://en.wikipedia.org/wiki/Equations_of_motion
There are also a number of online calculators you can use. See https://duckduckgo.com/?q=suvat+calculator&ia=web
jayjay said:ok so i need to find the mass like in kg? like for an exemple a 5 gallon bucket full of snow
anorlunda said:Yes. More important, you need to define "throw" numerically. How high? How fast? Is it fast enough that we need to consider air drag on the thrown object?
That puts in context. It is far easier to work with power than speed, acceleration and those equations of motion.jayjay said:well just trying to figure out how much force i need to the pulley to throw snow with a snowblower.
anorlunda said:That puts in context. It is far easier to work with power than speed, acceleration and those equations of motion.
First, figure out how much power your snow blower needs? Then, power=torque*RPM is the remaining formula.
You can buy snowblowers in the store with power ratings from 2 hp to 15 hp or more. Which of those fits your need?