Torque question need explaination

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Calculating torque requires specifying an origin because torque is dependent on the position vector relative to that origin. However, the magnitude of torque can be determined without an origin if the perpendicular force and distance to the axis of rotation are known. In the scenario with the mouse on the turntable, as the mouse walks clockwise, the turntable rotates counterclockwise due to the conservation of angular momentum and Newton's third law, which states that for every action, there is an equal and opposite reaction. The forces acting on the mouse and turntable balance out, resulting in the observed motion. Understanding these principles is crucial for solving problems related to torque and rotational dynamics.
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Homework Statement


1.Is it possible to calculate the torque acting on a rigid object without specifying an origin? Is the torque independent of the location of the origin?

2.A mouse is initially at rest on a horizontal turntable mounted on a frictionless vertical axle. If the mouse begins to walk clockwise around the perimeter of the table, what happens to the turntable? Explain using Newton's Laws.

Homework Equations


No,equation. Need to explain in words.

The Attempt at a Solution


for #1 i put no, we can't find torque without a specifying an origin since we won't know the length. But i don't get the 2nd part about the independent thing.

for #2 i put,
If the mouse is initially at rest on a horizontal turntable and walks at a clockwise direction, then the horizontal turntable will move in a counterclockwise direction. Using Newton's third law, the mouse is walking and does not accelerate so all the forces equals zero. Since all the forces equals to zero that means the forces the turntable exerts back the equal but opposite force back to the mouse.
 
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MikeMai said:

Homework Statement


1.Is it possible to calculate the torque acting on a rigid object without specifying an origin? Is the torque independent of the location of the origin?

2.A mouse is initially at rest on a horizontal turntable mounted on a frictionless vertical axle. If the mouse begins to walk clockwise around the perimeter of the table, what happens to the turntable? Explain using Newton's Laws.


Homework Equations


No,equation. Need to explain in words.

The Attempt at a Solution


for #1 i put no, we can't find torque without a specifying an origin since we won't know the length. But i don't get the 2nd part about the independent thing.

for #2 i put,
If the mouse is initially at rest on a horizontal turntable and walks at a clockwise direction, then the horizontal turntable will move in a counterclockwise direction. Using Newton's third law, the mouse is walking and does not accelerate so all the forces equals zero. Since all the forces equals to zero that means the forces the turntable exerts back the equal but opposite force back to the mouse.

It depends in what are you trying to calculate...

*As you know, torque is a vector, so, as a vector it has magnitude and direction. If you try to find \overrightarrow{\tau} the vector you have:

\overrightarrow{\tau}=\overrightarrow{r}\times \overrightarrow{F}

r: position vector F: force vector

In this case, you need a reference system

*If you are trying to find magnitude you have to calculate |\overrightarrow{\tau}|(usually in basic physics known as |\tau|=|r|\cdot |F|\cdot |\sin \theta|), in this case, you only need the F_{\perp} at the point you're interested in and the distance to the axis of turning, there's no need to put an origin.


Sometimes the problems with torque has lot of forces or asks for angular acceleration, so in this cases you need to work with them as vectors to get all the information.

I apologize if you don't understand something, my english isn't so advanced, I hope you understand... greetings!
 
Thank you for trying, those are the exact questions they asked me. So yeah...I need answer for the 2nd part of question #1, and confirmation of #2...

Would greatly appreciated if someone can help me out before midnight, 1h 30min left.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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