Calculating the Resulting Speed of a Student on a Turntable

  • Thread starter Thread starter ernay
  • Start date Start date
  • Tags Tags
    Student Turntable
Click For Summary
SUMMARY

The discussion centers on calculating the resulting speed of a student on a frictionless turntable. Given a student mass of 40 kg and a turntable mass of 400 kg with a diameter of 5 m, the initial angular velocity is 2 rev/min. Using the conservation of angular momentum, the final angular velocity of the student is determined to be 1.254 rad/s, resulting in a speed of 3.135 m/s. The student walks in the counterclockwise direction to bring the turntable to rest.

PREREQUISITES
  • Understanding of angular momentum conservation principles
  • Knowledge of moment of inertia calculations
  • Ability to convert between revolutions per minute and radians per second
  • Familiarity with kinematic equations relating linear and angular motion
NEXT STEPS
  • Study the conservation of angular momentum in closed systems
  • Learn about moment of inertia for various shapes and configurations
  • Explore the relationship between linear velocity and angular velocity
  • Investigate real-world applications of rotational dynamics in engineering
USEFUL FOR

Physics students, educators, and anyone interested in understanding rotational dynamics and angular momentum principles.

ernay
Messages
10
Reaction score
0

Homework Statement


A student of mass m=40 kg is standing on the edge of a uniform, frictionless turntable, with diameter d = 5m and mass M=400 kg. The student and the turntable are initially rotating counterclockwise together about a fixed axis through the center of the turntable with an angular velocity of wi = 2 rev/min.
The student now start to walk around the edge of the turntable so that the turntable comes to rest. What is the resulting speed v of the student relative to someone standing next to the turntable? In what direction is the student walking, clockwise or counter clockwise?

Homework Equations


conversion of rev/min to rad/s = rev/min * 1min/60s * 2(pi)/1rev
Conservation of angular momentum:
Li = Lf


The Attempt at a Solution


(Iturntable + Istudent)wi = Iturntable(wf) + Istudent(wfinal for student)
( (1/2)(400)(2.5)2 + (40)(2.5)2) (.209) = ( (1/2)(400)(2.5)2) (0) + ( (40)(2.5)2 ) wf

Solve for wf and I got 1.254 rad/s
Then use v = (r)wf = (2.5)(1.254) = 3.135 m/s
The student is walking in the counterclockwise direction

Can someone let me know if this is right? I thought it was too easy for a 30 point question
 
Physics news on Phys.org
I didn't plug in the numbers, but the method looks OK.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
5K
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
7
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K