Torque to speed reduction ratio

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SUMMARY

The discussion centers on calculating torque after reducing speed using a pulley system. A 200hp motor producing 600 ft-lbs of torque at 1750 RPM, when reduced to 190 RPM with a 9.2:1 pulley ratio, theoretically results in 5520 ft-lbs of torque. However, this value must be adjusted for losses due to friction in the pulley system, which can significantly affect the final torque output.

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bcarver
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hi,I was wondering if anybody would know the following:

If I have a 200hp motor that has 600ft/lbs of torque at 1750 rpm
and reduce the speed to 190 rpm with pulleys 9.2:1 does that
give me 600ft/lbs x 9.2 = 5520 ft/lbs torque @ 190 rpms?



thanks
 
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Yes, minus losses due to friction in the pulley system.
 

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