- #1
goodphy
- 216
- 8
Hello.
Let's have two electrons with same orbital quantum number li and these electrons are in antiparallel; one electron has magnetic quantum number mi = a and and other electron has mi = -a (but we don't know which one has ml = a as we're in coupled representation to talk about total angular momentum).
In this system, we know that total magnetic quantum number m is zero as [tex]m = \sum\limits_i {{m_i} = 0} .[/tex] m is allowed to be only 0 so total orbital quantum number l = 0 (l = 0 allows only m = 0). This is exact the same problem about total angular momentum for a closed shell in an atom.
So...can I simply conclude that total angular momentum (and also spin) is always zero for antiparallel electrons (antiparallel-spin electrons)?
Let's have two electrons with same orbital quantum number li and these electrons are in antiparallel; one electron has magnetic quantum number mi = a and and other electron has mi = -a (but we don't know which one has ml = a as we're in coupled representation to talk about total angular momentum).
In this system, we know that total magnetic quantum number m is zero as [tex]m = \sum\limits_i {{m_i} = 0} .[/tex] m is allowed to be only 0 so total orbital quantum number l = 0 (l = 0 allows only m = 0). This is exact the same problem about total angular momentum for a closed shell in an atom.
So...can I simply conclude that total angular momentum (and also spin) is always zero for antiparallel electrons (antiparallel-spin electrons)?