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Total angular momentum of hands of Big Ben

  1. Feb 13, 2009 #1
    Hello I just can't seem to get this problem right

    1. The problem statement, all variables and given/known data

    The hour and minute hands of Big Ben in London are 2.6 m and 4.58 m long and have masses of 68.6 kg and 97 kg respectively. Calculate the total angular momentum of the minute and hour hand about the center point. Treat the hand as long, thin rod. Treat “into the clock” as the positive direction. Answer in units of kg · m2/s.


    2. Relevant equations

    [tex]\omega = \frac{ 2\pi }{T}[/tex]

    [tex]I = \frac{1}{3} M R^2 [/tex]
    [tex]I = \frac{1}{12} M R^2 [/tex]?

    [tex]L = I \omega [/tex]

    3. The attempt at a solution

    Mmin= 68.6
    Mhour = 97

    lmin = 2.6
    lhour = 4.58

    [tex]\omega min = \frac{2\pi}{3600}[/tex]
    [tex]\omega hour = \frac{2\pi}{86400}[/tex]

    [tex]Imin = \frac{1}{3} Mmin lmin^2 [/tex] = 154.579
    [tex]Ihour = \frac{1}{3} Mhour lhour^2 [/tex] = 678.237

    [tex]Lmin = Imin \omega min[/tex] = 0.269791
    [tex]Lhour = Ihour \omega hour[/tex] = 0.0493228
     
  2. jcsd
  3. Feb 14, 2009 #2

    CompuChip

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    Science Advisor
    Homework Helper

    Your calculation looks all right, so probably you've just made a little mistake somewhere.

    Are you sure you aren't switching the minute and hour hands somewhere halfway? The hour hand is 2.6 m and 68.6 kg and the minute hand is 4.58 m and 97 kg. Are you using that consistently?

    You are giving two formulas for the moment of inertia, with 1/3 and 1/12 in front. Can you explain the difference?

    Also, don't forget your units, especially in the final answer (what is the unit of angular momentum?)
     
  4. Feb 17, 2009 #3
    Thanks I found out where I was wrong now, I was switching the mass numbers of minutes and hour hands.
     
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