Hello I just can't seem to get this problem right(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

The hour and minute hands of Big Ben in London are 2.6 m and 4.58 m long and have masses of 68.6 kg and 97 kg respectively. Calculate the total angular momentum of the minute and hour hand about the center point. Treat the hand as long, thin rod. Treat “into the clock” as the positive direction. Answer in units of kg · m2/s.

2. Relevant equations

[tex]\omega = \frac{ 2\pi }{T}[/tex]

[tex]I = \frac{1}{3} M R^2 [/tex]

[tex]I = \frac{1}{12} M R^2 [/tex]?

[tex]L = I \omega [/tex]

3. The attempt at a solution

Mmin= 68.6

Mhour = 97

lmin = 2.6

lhour = 4.58

[tex]\omega min = \frac{2\pi}{3600}[/tex]

[tex]\omega hour = \frac{2\pi}{86400}[/tex]

[tex]Imin = \frac{1}{3} Mmin lmin^2 [/tex] = 154.579

[tex]Ihour = \frac{1}{3} Mhour lhour^2 [/tex] = 678.237

[tex]Lmin = Imin \omega min[/tex] = 0.269791

[tex]Lhour = Ihour \omega hour[/tex] = 0.0493228

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# Total angular momentum of hands of Big Ben

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