1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Total Kinetic Energy in a System

  1. Apr 10, 2009 #1
    1. The problem statement, all variables and given/known data
    Using the total moment of inertia of the system, find the total kinetic energy of the system.

    Here is the diagram:

    134726A.jpg


    2. Relevant equations
    Find the total kinetic energy of the system using m, r, w.


    3. The attempt at a solution

    For particle a, I found the x and y components of inertia to be mr^2 and 9mr^2 respectively. I found the total y component of inertia of the system to be 11mr^2. I can't seem to find the total kinetic energy. I thought that if you take the original equation:

    K = 1/2mv^2 and plug in the components => K = 1/2m(r^2+9r^2) = 5mr^2 for particle A

    K = 1/2mv^2 and plug in the components => K = 1/2m(r^2+16r^2) = 17/2mr^2 for particle B

    Then add the two quantities to get 27/2mr^2w^2 for the kinetic energy. This isn't right...anything to help me would be much appreciated! Thanks!
     
  2. jcsd
  3. Apr 10, 2009 #2
    ...nvm I am only suppose to use the y-components for some reason. Thanks.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Total Kinetic Energy in a System
  1. Total Kinetic Energy (Replies: 1)

  2. Total Kinetic Energy (Replies: 1)

  3. Total kinetic Energy (Replies: 1)

Loading...