Total Load in PSI on Each Leg/Foot

[RWS000]

please see attachment FEET PSI. I am looking for the total load in psi on each leg/foot.
thanks very much

 

[Ray Vickson]

please see attachment FEET PSI. I am looking for the total load in psi on each leg/foot.
thanks very much

You are required to try it yourself first, and to report on the work you have done so far on the problem.

 

[RWS000]

Work I've done

Ray,
Thanks for your reply to my post.

Note: The magnitude of a torque is equal to the magnitude of the applied load multiplied by the distance between the objects axis of rotation and the point where the force is applied.
Thickness of base plate is 3/4".

Therefor: 450 ft/lbs x .0625 ft = 28.125 lbs
28.125 lbs divided by 3 supports = 9.375 lbs per support (3).
9.375 lbs divided by .11039 sq inches per support = 84.93 psi on each support.

I remain,
Roger

 

[SteamKing]

One problem with your calculation is that torque is measured in units of feet times pounds, or ft-lbs.