Total Load in PSI on Each Leg/Foot

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The discussion focuses on calculating the total load in psi on each leg or foot based on torque and support calculations. Roger outlines his methodology, stating that the torque of 450 ft-lbs, when applied over a distance of 0.0625 ft, results in a load of 28.125 lbs. This load is then distributed across three supports, yielding 9.375 lbs per support, which translates to 84.93 psi when divided by the area of 0.11039 sq inches per support. A correction is noted regarding the units of torque, emphasizing the importance of accurate unit measurement in calculations.

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please see attachment FEET PSI. I am looking for the total load in psi on each leg/foot.
thanks very much








 

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  • FEET PSI 001.jpg
    FEET PSI 001.jpg
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RWS000 said:
please see attachment FEET PSI. I am looking for the total load in psi on each leg/foot.
thanks very much

You are required to try it yourself first, and to report on the work you have done so far on the problem.
 
Work I've done

Ray,
Thanks for your reply to my post.

Note: The magnitude of a torque is equal to the magnitude of the applied load multiplied by the distance between the objects axis of rotation and the point where the force is applied.
Thickness of base plate is 3/4".

Therefor: 450 ft/lbs x .0625 ft = 28.125 lbs
28.125 lbs divided by 3 supports = 9.375 lbs per support (3).
9.375 lbs divided by .11039 sq inches per support = 84.93 psi on each support.

I remain,
Roger
 
One problem with your calculation is that torque is measured in units of feet times pounds, or ft-lbs.
 

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