Trying to determine actual load (PSI) on a drive chain

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Discussion Overview

The discussion revolves around determining the actual load in pounds per square inch (PSI) on a bicycle drive chain, particularly when climbing a mountain at a constant speed. Participants explore various aspects of force, torque, and pressure as they relate to bicycle mechanics, with a focus on calculating the load experienced by each chain link.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes a method to calculate the pressure on each chain link based on a constant pedaling pressure equivalent to lifting a 50-pound weight, suggesting a resulting pressure of 500 PSI.
  • Another participant challenges the initial calculation, noting that pounds is not a torque unit and that the force on the chain would be greater than the force applied to the pedals, depending on the radii of the crank and chain ring.
  • A third participant adds that being clipped in while mountain biking could effectively double the force exerted on the pedals, impacting the load on the chain.
  • One participant cites a claim from a chain lubricant manufacturer stating that the load on a bicycle chain can be around 65,000 PSI, although the method of arriving at this figure is unclear.
  • Another participant suggests that the elastic limit of the chain material could provide a more reliable estimate of stress, potentially aligning with the 65,000 PSI figure, but admits uncertainty regarding material properties.

Areas of Agreement / Disagreement

Participants express differing views on the calculation methods and the interpretation of forces involved, with no consensus on the correct approach or the validity of the cited PSI values.

Contextual Notes

Participants note the complexity of calculating contact pressure, which can vary based on multiple factors, and highlight the importance of understanding the definitions of force, torque, and pressure in this context.

maximiliano
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I think I have a rough idea how to get there...but I'm not sure.

Let's assume I'm riding a bicycle, and I'm peddling at a constant pressure (torque). This is a peddling pressure which would be the exact amount which would just lift a 50 pound weight off the ground and hold it there.

Okay...so as I'm peddling along, with precisely this much pressure on the chain...can I assume that is the EXACT pressure (in pounds) that each link of the chain is experiencing? IF SO, if I then calculate the surface area of each link that is exposed to peddling pressure to be 1/20" on one side of the pin and 1/20" on the other side, thus a total load bearing area of .1"...would I just then multiply the 50 pounds of total pressure by 10 (1 / .1)...for a total pounds per square inch being loaded on each link to be 500 psi??

Or...am I all wet on this calculation? What I'm attempting to do is to describe to some people how much actual pressure, in psi, each chain link is loaded by when someone is climbing a mountain at a constant speed. I used the 50 pounds of pressure as a guestimate of the torque required to do this. It's in that ballpark, but that number is not as important as it is to be able to calculate the PSI per link once the overall torque is known.

Thanks!
 
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Maybe not wet, but at least damp.

Pounds is not a torque unit.

If you put 50 pounds of force on the crank, then the maximum force on the chain will be bigger than that by the ratio of the radii of the crank and the front chain ring. The part of the chain that sees this force is the length on top between the chain ring and the cluster. The rest of the chain essentially sees zero load, except that produced by the tensioning device in the rear derailleur.

I have no idea what you are looking for in psi. If you are looking for the maximum stress in the chain, then figure the smallest cross sectional area of the steel in the chain. Divide the chain load figured above by that area. If you are looking for contact pressure between the chain and the sprockets, which will be highly variable as a function of many factors that get more complicated that we probably need to talk about here. But rest assured that contact pressure is very small.
 
I agree with Pkruse, with the exception that if you are mountain biking, you probably are strapped or clipped in. This could double the force (push and pull) that you exert on the pedals.

FYI:

Force is in Pounds (lbf) or Newtons (N)
Torque is in foot*pounds or inch*pounds or Newton*meters
Pressure is in Pounds per square inch or Newtons per square meter.
Another factor to consider is slip. You can only transmit as much force to the chain as the tire/ground will give back. If your bike is throwing more force to the ground than the ground will put back (called traction) your tire will slip. This is not an uncommon scenario at least when I am mountain biking.
 
according to the manufacture of A.T.B. (absolutely the best) chain lubricants.
K. Lewis enterprises claims that the load on a bicycle chain is roughly 65,000 psi.
I don't know what procedure they used to come to this number.
just relaying the info.
Looking forward to some explanation!
 
lipster94 said:
according to the manufacture of A.T.B. (absolutely the best) chain lubricants.
K. Lewis enterprises claims that the load on a bicycle chain is roughly 65,000 psi.
I don't know what procedure they used to come to this number.
just relaying the info.
Looking forward to some explanation!

link?
 
i don't think he has a website.
his name is Keith Lewis and makes the lube himself.
I heard this over a phone conversation...
 
lipster94 said:
I don't know what procedure they used to come to this number.
just relaying the info.

You could skip all the guessing about force on the pedals etc, and just take the elastic limit of the chain material - i.e. the stress level that would stretch the chain permanently.

That would probably give a number in the ballpark of 65,000 psi, but I'm no expert on the material properties of bike chains!
 

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