Total spin of triplet and singlet states

  • Context: Graduate 
  • Thread starter Thread starter K448
  • Start date Start date
  • Tags Tags
    Singlet Spin States
Click For Summary

Discussion Overview

The discussion revolves around the total spin of triplet and singlet states in quantum mechanics, specifically addressing how to determine the total spin S for the states represented by the combinations ↑↓+↓↑ and ↑↓-↓↑. Participants also explore the computation of the total magnetic spin quantum number (ms) for these states.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Homework-related

Main Points Raised

  • One participant expresses confusion about how the total spin S is determined to be 1 for the state ↑↓+↓↑ and 0 for the state ↑↓-↓↑.
  • Another participant suggests applying the squared total spin operator ##\mathbf{S}^2 = (\mathbf{S_1}+\mathbf{S_2})^2## to find the total spin for the states.
  • It is mentioned that the total magnetic spin quantum number (ms) can be computed using the operator ##S_z = S_{1z} + S_{2z}##, and that the z component of the resultant spin state corresponds to the sum of the z components of the individual states.
  • A later reply indicates a lack of familiarity with the total spin operator and requests recommended readings on the topic.
  • Participants recommend specific textbooks, including "Introduction to QM" by Griffith and "Modern QM" by Sakurai, as well as MIT's open course material for further study.

Areas of Agreement / Disagreement

Participants generally agree on the methods to compute total spin and magnetic spin quantum numbers, but there is no consensus on the understanding of the total spin operator itself, as one participant expresses confusion about it.

Contextual Notes

Some participants mention the need for foundational knowledge regarding the total spin operator, indicating a potential gap in understanding that may affect the discussion.

K448
Messages
3
Reaction score
0
I'm a litte confused about spin triplet and singlet states. How do we know that for ↑↓+↓↑ the total spin S is 1, and for ↑↓-↓↑ the total spin S is 0?
Also, how is total ms computed for these two states? (I understand that they are both 0, but not sure where that comes from)

Thank you very much for the help!
 
Physics news on Phys.org
K448 said:
How do we know that for ↑↓+↓↑ the total spin S is 1, and for ↑↓-↓↑ the total spin S is 0?
Apply the (squared) total spin operator ##\mathbf{S}^2 = (\mathbf{S_1}+\mathbf{S_2})^2## to those states.
K448 said:
Also, how is total ms computed for these two states
Apply the operator ##S_z = S_{1z} + S_{2z}## to those states. Alternatively, upon following the theorem of the addition of angular momenta, you will find that the z component of the resultant spin state is equal to the sum of the z components of the individual states appearing in the resultant state's representation in the individual spin state basis.
 
blue_leaf77 said:
Apply the (squared) total spin operator ##\mathbf{S}^2 = (\mathbf{S_1}+\mathbf{S_2})^2## to those states.

Apply the operator ##S_z = S_{1z} + S_{2z}## to those states. Alternatively, upon following the theorem of the addition of angular momenta, you will find that the z component of the resultant spin state is equal to the sum of the z components of the individual states appearing in the resultant state's representation in the individual spin state basis.
Thank you very much! I realize I never learned the total spin operator... Is there a recommended reading about this?
 
blue_leaf77 said:
Introduction to QM by Griffith chapter 4 or Modern QM by Sakurai chapter 3. The latter is more advanced than the former but especially on the addition of angular momenta and it's in fact my favorite QM book, I found it still easy to understand. Alternatively MIT's opencourse material will also do http://ocw.mit.edu/courses/physics/...all-2013/lecture-notes/MIT8_05F13_Chap_10.pdf
Thank you! :)
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 14 ·
Replies
14
Views
6K