Total time wagon needs to fully pass the hopper

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Homework Help Overview

The problem involves a train wagon of mass M moving at a constant velocity V while passing under a sand hopper that adds mass to the wagon at a constant rate C. The length of the wagon is L, and the discussion centers around determining the velocity of the wagon as a function of time and calculating the total time it takes for the wagon to fully pass the hopper.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum to derive the velocity of the wagon as it accumulates sand. There are attempts to integrate equations related to motion and momentum, with some participants expressing confusion over the complexity of the equations and the integration process.

Discussion Status

Some participants have provided guidance on simplifying the approach, suggesting that the constant acceleration equations may not be applicable. There is an ongoing exploration of the relationship between velocity, distance, and time, with participants questioning their own reasoning and calculations.

Contextual Notes

Participants note the need to set appropriate limits for integration and the potential for missing factors in their equations. There is an acknowledgment of the complexity of the problem, with some expressing frustration over the integration process and the resulting equations.

freutel
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Homework Statement


A train wagon of mass M moves on a rail with constant velocity V (without friction). It passes a sand hopper which pours sand in the wagon at constant rate C [kg/s]. The sand falls vertically so it does not transfer any horizontal momentum to the wagon. The length of the wagon is L [m].
Question 1: Determine the velocity of the train wagon as a function of time V(t) while it is under the sand hopper.
Question 2: Show that the total time T that it takes for the wagon to fully pass the hopper machine is T=M/C*(exp(CL/MV)-1)

Homework Equations


  • Conservation of momentum MwagonV0=(Mwagon+msand)*V1
  • F=ma=dP/dt (Newton's second law)
  • t=msand/C
  • Straight-line motion equations
vx=v0x+axt (Equation 1)

x=x0+v0xt+½axt2 (Equation 2)

vx2=v0x2+2a(x-x0) (Equation 3)

x-x0=½(v0x+vx)t (Equation 4)


The Attempt at a Solution



The first question was pretty easy. Because I need the answer from question 1 to solve question 2 I want to make sure that I have the right answer for question 1.
Question 1:
Using conservation of momentum I got MwagonV0=(Mwagon+msand)*V1 and the mass of the sand can be written as Ct. Subbing that in you get MwagonV0=(Mwagon+Ct)*Vt. This gives an equation for Vt -> Vt=Mwagon*V0/(Ct+Mwagon)

Question 2:
This one is tricky and it definitely needs integrating if you look at the equation. I have a feeling there are multiple ways to approach this but every approach I did ended up in chaotic equations that did not help. First I used Newton's second law --> F=dP/dt
Pt=Mtvt with the mass being dependent of time because of Mwagon+Ct

dP/dt=Mtdv/dt+vtdm/dt (dm/dt is the change in mass per unit time which is C)

F=Mtdv/dt+Cvt

When isolating dV/dt and integrating that I got

V=(F-CV)ln(M2+C2T2)

M2+C2T2=exp(V/(F-CV)

This is definitely going in the wrong direction and I got no L in the equations.

Then I started with equation 2 with x being L --> L=V0t+½at2.

Acceleration is dV/dt which is CMV/((Ct+M)2) but subbing this in gives again nothing I can work with.

Then I used equation 3 which resulted in

(MV)2/((M+Ct)2)=V02+2(dV/dt)*L

Isolating dV/dt gives

-C2t2V2/(2(M2L+C2T2L)=dV/dt

This is also a pain to integrate but I used an integration calculator and I ended up with an arctan in my equation.

This is going nowhere and I would really appreciate some help.
 
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Hi, freutel.

The constant acceleration equations that you wrote as relevant equations are not applicable in this problem.

You're making it more difficult than necessary. You found from question 1 that Vt=Mwagon*V0/(Ct+Mwagon).
Can you see what to do if you write Vt = dx/dt?
 
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I always fail to see the easiest way to solve the problem..
Ok so I did Vt=dx/dt which gives x=((MwagonV)/C)*ln(Mwagon+Ct)
The x is of course L so I isolated everything from the natural log which gives LC/(MwagonV)=ln(Mwagon+Ct)
This results in Mwagon+Ct=exp(CL/MwagonV).
Now I get for t --> t=(1/C)*exp((CL/MwagonV)-M/C.

It appears I am missing a factor M at the exponential function... I'm looking for that missing M but I cannot find it. Did I oversee something or could it be that the given equation has a factor M too many?
 
TSny said:
Hi, freutel.

The constant acceleration equations that you wrote as relevant equations are not applicable in this problem.

You're making it more difficult than necessary. You found from question 1 that Vt=Mwagon*V0/(Ct+Mwagon).
Can you see what to do if you write Vt = dx/dt?

I know you are not supposed to give full answers but I really cannot find that missing M. Can you please help me?
 
When you integrate you can either do indefinite integrals or definite integrals.

If you use indefinite integrals, you will have an arbitrary constant of integration that you will need to determine.

If you use definite integrals, then make sure you use the appropriate limits of integration for x and t and evaluate the integrals at both the upper and lower limits.
 
Yes! I made a little mistake, I forgot to set the boundaries from 0 to T but now I got it!
Thank you very much, TSny!
 
OK. Good work!
 

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