Towing two stacked boxes up a ramp

  • Thread starter Thread starter Sebee_ulg
  • Start date Start date
  • Tags Tags
    Force
Click For Summary
The discussion centers on calculating the forces and velocity involved in towing two stacked boxes up a ramp, with initial answers provided as approximately 675 N for force (a), 859 N for force (b), and 2.2 m/s for velocity (c). A participant expresses difficulty in obtaining the correct result for question b and seeks guidance. The conversation emphasizes the importance of drawing Free Body Diagrams for both boxes to analyze the forces acting on them. Participants are encouraged to clarify their understanding of the relevant equations needed for the problem. The thread highlights the necessity of following homework help guidelines for effective assistance.
Sebee_ulg
Messages
2
Reaction score
0
New poster is reminded to always show their work when starting schoolwork threads
Homework Statement
A man pulls two boxes along a ramp of length L = 4.75 m and height H = 2.5 m. To do this, he pulls on a rope attached to the first box of mass m1 = 48 kg. The second box has a mass m2 = 32 kg and is placed on top of the first. The coefficient of friction between the first box and the floor is µ1 = 0.444 and the coefficient of friction between the two boxes is µ2 = 0.8.
Relevant Equations
(a) the force to be applied to move the two boxes at a constant speed constant v = 1.5 m/s. (b) the maximum force that can be applied to the string to ensure that the two boxes to remain stationary relative to each other. (c) What will be the speed of the boxes after travelling 1 m?
Answer is (a) F ≃ 675 (N); (b) F ≃ 859 (N) (c) v ≃ 2.2 (m/s).
 
Physics news on Phys.org
Sebee_ulg said:
Sorry, I hadn't read the instructions and my question is that I can't find the right result for question b.
Mainly: what is your best effort ?

And: what are the relevant equations you need to get going on this exercise ?

##\ ##
 
Last edited:
Sebee_ulg said:
Sorry, I hadn't read the instructions and my question is that I can't find the right result for question b.
Have you drawn Free Body Diagrams for both boxes?
If they do not stay together, what can you say about the forces between them?
 
Thread 'Chain falling out of a horizontal tube onto a table'

Thread 'Chain falling out of a horizontal tube onto a table'

My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
View full post »

Similar threads

Acceleration & Normal Force of a Box: 4 m/s2 & 418 N
  • · Replies 9 ·
Replies
9
Views
2K
Truck accelerating down a ramp
  • · Replies 10 ·
Replies
10
Views
1K
Stacked blocks & pulley system
  • · Replies 7 ·
Replies
7
Views
292
Acceleration of an Electron in a Uniform Electric Field
  • · Replies 2 ·
Replies
2
Views
587
Efficiency of Ramp: Solving Box Push Up Problem
  • · Replies 3 ·
Replies
3
Views
3K
Box and a Spring on on an inclined plane
  • · Replies 11 ·
Replies
11
Views
3K
Cirular Motion - car on a circular ramp
  • · Replies 4 ·
Replies
4
Views
2K
Simple Ramp motion problem, but going full vector mode
  • · Replies 29 ·
Replies
29
Views
2K
Need help on a work problem -- Pushing a shoe box up a ramp
  • · Replies 8 ·
Replies
8
Views
2K
Work done pushing a refrigerator up an Incline
  • · Replies 6 ·
Replies
6
Views
2K