Trace Theorems and Dirac Matrices

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The discussion centers on confusion regarding trace theorems and Dirac matrices, specifically the equation from Peskin and Schroeder that states gamma^(mu)*gamma^(nu)*gamma_(mu) = -2*gamma^(nu). The user initially attempts to manipulate the equation through anti-commutation but arrives at a contradiction. Clarification reveals that they overlooked a crucial aspect of the anti-commutation relation, which includes an additional term involving the metric tensor. The user acknowledges this oversight and humorously considers taking a break from physics. Understanding the full anti-commutation relation is essential for resolving the confusion.
dm4b
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I think I'm missing something real simple on trace theorems and Dirac matrices, but am just not seeing it.

In the Peskin and Schroeder QFT text on page 135 we have:

gamma^(mu)*gamma^(nu)*gamma_(mu) = -2*gamma^(nu)

But, why can't we anti-commute and obtain the following:

gamma^(mu)*gamma^(nu)*gamma_(mu)
= -gamma^(nu)*gamma^(mu)*gamma_(mu)
= -4*gamma^(nu)

which contradicts the equation above?

Any help would be much appreciated. Thanks!

P.S. ^=superscript, and _=subscript (LATEX wasn't working for me)
 
Last edited:
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dm4b said:
But, why can't we anti-commute and obtain the following:

gamma^(mu)*gamma^(nu)*gamma_(mu)
= -gamma^(nu)*gamma^(mu)*gamma_(mu)
= -4*gamma^(nu)

You missed part of the anticommutation relation:

\gamma^\mu \gamma^\nu \gamma_\mu = \left( -\gamma^\nu \gamma^\mu + 2\eta^{\mu\nu} \right) \gamma_\mu.
 
doh! thanks ... maybe I better take a break from doing physics now ;-)
 
Last edited:
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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