MHB Train Velocity-Time Graph: Uniform Acceleration and Retardation Motion Explained

Click For Summary
SUMMARY

The discussion focuses on the motion of a train experiencing uniform acceleration, uniform velocity, and uniform retardation. The train accelerates at 0.5 m/s² for 20 seconds, travels at a constant speed for 30 seconds, and then decelerates to rest over 10 seconds. The velocity-time graph for this motion forms a trapezium, and the total distance traveled can be calculated using the area of this trapezium.

PREREQUISITES
  • Understanding of kinematic equations, specifically the formula for velocity with uniform acceleration: v = v₀ + a t.
  • Knowledge of how to sketch velocity-time graphs.
  • Familiarity with calculating areas of geometric shapes, particularly trapeziums.
  • Basic concepts of uniform acceleration and retardation in physics.
NEXT STEPS
  • Learn how to derive and apply kinematic equations in various motion scenarios.
  • Study the principles of graphing motion, including velocity-time and position-time graphs.
  • Explore the calculation of areas under curves to determine distance traveled in physics.
  • Investigate real-world applications of uniform acceleration and retardation in transportation systems.
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion dynamics and graph interpretation.

Jerome1
Messages
17
Reaction score
0
A train starts from rest from a station and travels with uniform acceleration 0.5m/s^2 for 20s. it travels with uniform velocity for another 30s, the brakes are then applied so that a uniform retardation is obtained and the train comes to rest in a further 10s. sketch the velocity-time graph of this motion. Using your graph, calculate the total distance traveled by the train

please can i see the graph, and also include explanation so that i can understand better
 
Mathematics news on Phys.org
First, let me ask you if the velocity changes uniformly, that is, the acceleration is constant, how will the velocity vary, mathematically speaking?
 
i don't have answers to that.
 
Welcome to MHB, Jerome! :)

Jerome said:
A train starts from rest from a station and travels with uniform acceleration 0.5m/s^2 for 20s. it travels with uniform velocity for another 30s, the brakes are then applied so that a uniform retardation is obtained and the train comes to rest in a further 10s. sketch the velocity-time graph of this motion. Using your graph, calculate the total distance traveled by the train

please can i see the graph, and also include explanation so that i can understand better

Jerome said:
i don't have answers to that.

The formula for velocity with uniform acceleration is:
$$v = v_0 + a t$$
where $v$ is the speed at time $t$, $v_0$ is the initial speed, and $a$ is the uniform acceleration.

Is this formula known to you?

Anyway, in your problem, we can deduce that $v_0 = 0$, since the train is initially at rest.
And $a=0.5 m/s^2$ is given.

Do you know how to draw the graph of $v=0.5 t$ for the time period of 0 to 20s?
What will be the speed at $t=20s$?
 
I like Serena said:
Welcome to MHB, Jerome! :)The formula for velocity with uniform acceleration is:
$$v = v_0 + a t$$
where $v$ is the speed at time $t$, $v_0$ is the initial speed, and $a$ is the uniform acceleration.

Is this formula known to you?

Anyway, in your problem, we can deduce that $v_0 = 0$, since the train is initially at rest.
And $a=0.5 m/s^2$ is given.

Do you know how to draw the graph of $v=0.5 t$ for the time period of 0 to 20s?
What will be the speed at $t=20s$?
i got that thanks, the graph looks like a trapezium, so the area of the trapezium is the total distance right?
 
Jerome said:
i got that thanks, the graph looks like a trapezium, so the area of the trapezium is the total distance right?

Yep!
 

Similar threads

Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 22 ·
Replies
22
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K