Transform Diff. Eq: Ordinary to More Convenient Expression

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Discussion Overview

The discussion revolves around transforming a differential equation into a more convenient expression for integration. Participants explore various forms of the equation and seek clarity on the conditions for integration and the nature of the functions involved.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant seeks to transform the differential equation \((1/r)*(dy/dr)*(d^2/dr^2(r*y))*dr\) into a simpler form similar to \((dy/dx)*(d^2y/dx^2)*dx = 0.5*(d/dx(dy/dx)^2)*dx\) for easier integration.
  • Another participant points out the absence of an equality in the original equation, suggesting that it is unclear as presented.
  • Clarifications are made regarding the use of variables "x" and "r," with one participant acknowledging a mix-up and emphasizing the need for consistency in variable usage.
  • There is a suggestion that multiplying the second equation by \(x^4\) could facilitate integration, although the nature of the equation is debated.
  • One participant expresses confusion about addressing the equation as homogeneous and notes that the term \(x^4\) cannot be eliminated but can be integrated.
  • A separate question arises regarding the analyticity of functions in the context of power series solutions to ordinary differential equations, specifically questioning how \(x\) and \(x^2\) can be considered analytic despite their derivatives eventually becoming zero.
  • Responses clarify that \(x^2\) is infinitely differentiable, as its derivatives eventually become constant, leading to zero for higher derivatives.

Areas of Agreement / Disagreement

Participants express differing views on the transformation of the differential equation and the conditions for integration. There is no consensus on how to best approach the original equation, and the discussion on analyticity remains unresolved with varying interpretations of differentiability.

Contextual Notes

The discussion includes limitations related to the clarity of the original equation, the definitions of terms used, and the assumptions regarding the nature of the functions involved in the differential equations.

tbk1
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I wish to transform my diff. eq.
(1/r)*(dy/dr)*(d2/dr2(r*y))*dr into a more convenient expression, in a similar to the following transformation:

(dy/dx)*(d2y/dx2)*dx = 0.5*(d/dx(dy/dx)^2)*dx
which is a very convenient expression for integration ==> 0.5* (dy/dx)^2

So far, I have found the following expression, to which I haven't found the integration answer.
(1/(2*x^4)*(d/dx(x^2*dy/dx)^2)

I would appreciate your help
tbk1
 
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If you want to solve something, you need an equation. I do not see any "=" in your problem.
Your first expression has an additional dr which I would not expect there.

Converted to LaTeX, as it is easier to read:
$$\frac{1}{r} \left(\frac{dy}{dr}\right) \left(\frac{d^2}{dr^2} (ry)\right) dr$$
$$\frac{1}{2x^4}\frac{d}{dx} \left(x^2 \frac{dy}{dx}\right)^2$$
 
Thank you for your quick reply. I do not LaTex, so till I'll find a quick way to translate it, I wish to make the following remarks:
1. You're right, a differential, dr, is missing of course.
2. You may address it as an homogeneous equation, but the truth is that I simply seek the simpler expression to integrate, something like d(f(x))dx, so that the integral result will be
3. I mixed "x" and "r", all the independent variables should be either "x" or "r".
Thanks again
tbk1
 
The second equation looks good in that respect. Multiply with x^4, and you can integrate both sides. The left side is trivial (as it is df(x)/dx), the right side is 0 or something you can integrate, and afterwards you can try to simplify the result to integrate again.
 
oops, reading your reply, I understand that one cannot address the equation as a homogeneous one, but rather as equal to a constant, than the term "x^4" cannot be eliminated.
 
tbk1 said:
I wish to transform my diff. eq.
(1/r)*(dy/dr)*(d2/dr2(r*y))*dr into a more convenient expression, in a similar to the following transformation:

(dy/dx)*(d2y/dx2)*dx = 0.5*(d/dx(dy/dx)^2)*dx
which is a very convenient expression for integration ==> 0.5* (dy/dx)^2

So far, I have found the following expression, to which I haven't found the integration answer.
(1/(2*x^4)*(d/dx(x^2*dy/dx)^2)

I would appreciate your help
tbk1

Hi !
Fishy wording ! I cannot understand exactly what is the equation.
Would you mind rewrite only the first equation, without explanation nor comment which could confused us. Only one equation on the patern :
(1/r)*(dy/dr)*(d2/dr2(r*y)) = what ?
 
tbk1 said:
oops, reading your reply, I understand that one cannot address the equation as a homogeneous one, but rather as equal to a constant, than the term "x^4" cannot be eliminated.
It cannot be eliminated, but it is easy to integrate it with respect to x.
 
Hi,
I have a question regarding to the series solution of ordinary differential equation . my question is , I've found that if we have to solve y"+p(x)y'+q(x)y=0 by power series method, we have to find a point say "a" where p(x) & q(x) become analytic , and by the definition of analytic function a function will be analytic if it has a taylor series expansion around a given neighbourhood point and for taylor series expansion the function must be infinitely differentiable but for the equation y"+xy'+x^2y=0. how x & x^2 become analytic as by the 2 differentiation of x and 3 differentiation of x^2 it becomes zero , and so there not infinitely differentiable ?
Thanx in advance
 
Shan K said:
how x & x^2 become analytic as by the 2 differentiation of x and 3 differentiation of x^2 it becomes zero , and so there not infinitely differentiable ?
The first derivative of x² is 2x
The second derivative is 2
The third derivative is 0 because the derivative of any constant function is 0.
The fourth derivative is 0 because the derivative of any constant function is 0.
And so on. All successive derivatives are 0.
So, x² is infinitely differentiable.
 
  • #10
JJacquelin said:
The first derivative of x² is 2x
The second derivative is 2
The third derivative is 0 because the derivative of any constant function is 0.
The fourth derivative is 0 because the derivative of any constant function is 0.
And so on. All successive derivatives are 0.
So, x² is infinitely differentiable.

Thanx
 

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