Transform from one position to another.

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SUMMARY

The discussion focuses on transforming the Contravariant Position Vector using the Schwarzschild Metric in general relativity. The initial vector is defined as ##x^{k} = \left[ r, \theta, \phi, t \right]## with specific values for each component. The goal is to compute the new vector ##x^{k'}## by applying the transformation matrix ##\Lambda^{k'}_k##, which incorporates the Riemann Curvature Tensor or the Christoffel Symbol due to the small change in time, ##\Delta t##, defined as the period of one revolution divided by 10000. This transformation is crucial for understanding the dynamics of objects in a gravitational field.

PREREQUISITES
  • Understanding of the Schwarzschild Metric and its application in general relativity.
  • Familiarity with Contravariant and Covariant vectors in tensor calculus.
  • Knowledge of Christoffel Symbols and their role in geodesic equations.
  • Basic concepts of Riemann Curvature Tensor and its significance in differential geometry.
NEXT STEPS
  • Study the derivation and application of the Schwarzschild Metric in various gravitational scenarios.
  • Learn about the computation and significance of the Riemann Curvature Tensor in general relativity.
  • Explore the properties and applications of Christoffel Symbols in calculating geodesics.
  • Investigate the implications of small perturbations in time on the motion of objects in a gravitational field.
USEFUL FOR

This discussion is beneficial for physicists, mathematicians, and students studying general relativity, particularly those interested in the mathematical framework of gravitational theories and tensor calculus.

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Homework Statement



Using the Schwarzschild Metric and the Contravariant Position Vector 1x4 ##x^k## with 4 vector:

$$x^{k'} = \left[ \begin {array}{c}r \\ \theta \\ \phi \\ t \end {array} \right]$$


where
##x^1## = r = 1 per unit distance
##x^2## = ##\theta## = 50 Degrees
##x^3## = ##\phi## = 30 Degrees
##x^4## = t = 1 per unit time

Find the next Contravariant Position Vector 1x4 ##x'^k##

where ##\Delta##t = t' - t = Period of One Revolution (in per unit time) / 10000

$$x^{k'} = \left[ \begin {array}{c}r' \\ \theta' \\ \phi' \\ t' \end {array} \right]$$

Homework Equations



Covarient Schwarzschild Metric Tensor 4x4
$$g_{ij} = \left[ \begin {array}{cccc}1/(1-2m/r) & 0 & 0 & 0 \\ 0 & r^2 & 0 & 0 \\ 0 & 0 & r^2(sin(h))^2 & 0\\ 0 & 0 & 0 & -(1-2m/r) \end {array} \right]$$

Contravarient Schwarzschild Metric Tensor 4x4
$$g^{ij} = (g_{ij})^{-1}$$

Christoffel Symbol of Affinity 4x4x4
##\Gamma^i_{jk}## = 1/2*##g^{il}## * (##\frac{d g_{lj}}{d x^k}## + ##\frac{d g_{lk}}{d x^j}## - ##\frac{d g_{jk}}{d x^l}##)

Riemann Curvature Tensor 4x4x4x4
##R^i_{jkl}## = ##\frac{d \Gamma^i_{jl}}{d x^k}## - ##\frac{d \Gamma^i_{jk}}{d x^l}## + ##\Gamma^i_{km}## * ##\Gamma^m_{jl}## - ##\Gamma^i_{lm}## * ##\Gamma^m_{jk}##


The Attempt at a Solution




##x^{k'} = \Lambda^{k'}_k * x^k##

##\Lambda^{k'}_k## 4x4 should contain a form of the Riemann Curvature Tensor or the Christoffel Symbol because ##\Delta##t is reasonably small.
 
Last edited:
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Period of One Revolution (in per unit time) / 10000
What does that mean?
 
The time the object takes to orbit the central body in per unit time divided by 10000. What I really mean is a Deltat small enough to have a homogeneous Riemann and Christoffel.
 
Last edited:

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