Transformation of a vector operator

Click For Summary
SUMMARY

The discussion focuses on the transformation of the vector operator \(\hat{V_{y}}\) by the rotation operator \(\hat{R_{x}}\) around an angle \(\alpha\). The rotation operator is defined as \(\hat{R_{x}} = \begin{pmatrix} 1& 0& 0\\ 0& \cos\alpha & -\sin\alpha \\ 0 & \sin\alpha & \cos\alpha \end{pmatrix}\). The participants clarify that the transformation involves applying the rotation operator to the vector operator, leading to the expression \(V_i \to R_{ij} V_j\). The confusion lies in understanding how the matrix representation of the rotation operator corresponds to its action on quantum states.

PREREQUISITES
  • Understanding of vector operators in quantum mechanics
  • Familiarity with rotation matrices and their properties
  • Knowledge of quantum state representations (kets and wave functions)
  • Basic linear algebra concepts, particularly matrix multiplication
NEXT STEPS
  • Study the mathematical representation of quantum operators and their transformations
  • Learn about the implications of rotation operators in quantum mechanics
  • Explore the relationship between classical rotation matrices and quantum mechanical operators
  • Investigate the application of the transformation \(V_i \to R_{ij} V_j\) in practical quantum mechanics problems
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on operator transformations and their applications in quantum state manipulation.

andre220
Messages
75
Reaction score
1

Homework Statement



Calculate the result of the transformation of the vector operator [tex]\hat{V_{y}}[/tex] by rotation [tex]\hat{R_{x}}[/tex] around an angle [tex]\alpha[/tex].



Homework Equations



I believe that [tex]\hat{R_{x}} = \begin{pmatrix} 1& 0& 0\\ 0& cos\alpha & -sin\alpha \\ 0 & sin\alpha & cos\alpha \end{pmatrix}[/tex]

Not sure if the fact that it is an operator makes any difference here...

The Attempt at a Solution



So at first glance it seems that the solution should be something like the calculation of [tex]\hat{V_y} \hat{R_x}[/tex], however I am not sure since they are operators. If this is correct then would the solution be calculated by using arbitrary components of [tex]\hat{V_y}[/tex]? If this is completely wrong, what is a better way to look at this problem?

Thank you for any help.
 
Physics news on Phys.org
Let's start with a more basic question: given a rotation

[tex]R_{x} = \begin{pmatrix} 1& 0& 0\\ 0& cos\alpha & -sin\alpha \\ 0 & sin\alpha & cos\alpha \end{pmatrix},[/tex]

what is the corresponding operator [itex]\hat{R_{x}}[/itex] that acts on states (kets or wave functions)?
 
I guess that is what I am most confused about here. Is how does [tex]R_x[/tex] come correspond to [tex]\hat{R_x}[/tex].

So some thing like this: [tex]V_i \to R_{ij} V_j[/tex]


If I had to make an educated guess here I would say it would transform on the ket [tex]\mid \psi \rangle[/tex] in this way: [tex]\langle \psi \mid V_i \mid \psi \rangle \to R_{ij} \langle \psi \mid V_j \mid \psi \rangle[/tex].
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K