Translating motion graphs. Dt to vt

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SUMMARY

This discussion centers on translating position-time graphs (d-t) to velocity-time graphs (v-t) in motion analysis. When a curve in the d-t graph indicates accelerated motion, it translates to a diagonal line in the v-t graph, reflecting constant rate of change in velocity. The diagonal line in the d-t graph represents constant velocity, which corresponds to a horizontal line in the v-t graph. A step function is only applicable when transitioning between two constant speeds, which is not the case in the discussed scenario.

PREREQUISITES
  • Understanding of position-time (d-t) and velocity-time (v-t) graphs
  • Knowledge of motion concepts, specifically uniform acceleration
  • Familiarity with graphical representation of motion
  • Basic calculus principles related to slopes and rates of change
NEXT STEPS
  • Study the principles of translating d-t graphs to v-t graphs
  • Learn about uniform acceleration and its graphical representation
  • Explore the concept of step functions in motion analysis
  • Review examples of parabolic motion and its implications on velocity graphs
USEFUL FOR

Students and educators in physics, particularly those focused on kinematics, as well as anyone involved in teaching or learning about motion graph translations.

kencamarador
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I am so confuse! It's regarding translating motion graphs.

When translating a position time graph to a velocity time graph, if a curve line is followed by a straight diagonal line (both going up) do I use a step function?

Cause in this video http://m.youtube.com/#/watch?v=EZXLkAYjmR0&desktop_uri=/watch?v=EZXLkAYjmR0

At 3:04. He drew a diagnal line without calculating the slope... Isn't he suppose to use a step function?
 
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kencamarador said:
I am so confuse! It's regarding translating motion graphs.

When translating a position time graph to a velocity time graph, if a curve line is followed by a straight diagonal line (both going up) do I use a step function?

Cause in this video http://m.youtube.com/#/watch?v=EZXLkAYjmR0&desktop_uri=/watch?v=EZXLkAYjmR0

At 3:04. He drew a diagnal line without calculating the slope... Isn't he suppose to use a step function?

The two sloping sections before and after the curved line can be used to find the constant velocities before and after the acceleration section. The presenter has possibly assumed [for simlicity] that the acceleration between those two sections was constant. Does the curved section look like it may be parabolic? [I can't play the video].
 
kencamarador said:
He drew a diagnal line without calculating the slope... Isn't he suppose to use a step function?

No, he souldn't use a step function in such a case.
Curve line in d-t representation means accelerated motion (suppose the curve line is a parabola for simplicity, i.e. uniform acceleration)... then in the v-t representation it is a diagonal line, meaning that velocity is changing at constant rate.

Then the diagonal line in d-t representation means constant velocity. In v-t representation this is instead a straight horizontal line.

Therefore what you get is a diagonal line joined to an horizontal line. You would have a step function in v-t representation only in case you have two motions both at constant speed but with different speed (and at some point speed has to change instantaneously but you do not know why, it is not a realistic situation of course); in this case the d-t representation would be just two diagonal lines with different slopes.
 

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