Translation Invariance of Outer Measure .... Axler, Result 2.7 ....

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SUMMARY

The discussion centers on Result 2.7 from Sheldon Axler's book, "Measure, Integration & Real Analysis," specifically regarding the proof of the inequality |t + A| ≤ |A|. Participants clarify that the infimum of the sums of the lengths of open intervals I_k, which cover set A, establishes a lower bound for |t + A|. This is rooted in the principle that weak inequalities are preserved by limits, meaning if all elements of a set satisfy a weak inequality, so does the limit of that set. The conversation emphasizes the importance of understanding sup and inf in the context of limits.

PREREQUISITES
  • Understanding of measure theory concepts, particularly outer measure
  • Familiarity with the definitions of infimum and supremum
  • Knowledge of open intervals and their properties in real analysis
  • Basic grasp of inequalities and their implications in mathematical proofs
NEXT STEPS
  • Study the concept of outer measure in depth, particularly in the context of real analysis
  • Learn about the properties of infimum and supremum in mathematical analysis
  • Explore the implications of weak inequalities in limit processes
  • Review additional examples of measure theory proofs from Axler's "Measure, Integration & Real Analysis"
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Mathematicians, students of real analysis, and anyone studying measure theory who seeks to deepen their understanding of outer measures and inequalities in mathematical proofs.

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I am reading Sheldon Axler's book: Measure, Integration & Real Analysis ... and I am focused on Chapter 2: Measures ...

I need help with the proof of Result 2.7 ...

Result 2.7 and its proof read as follows:
Axler - Result  2.7 - outer measure is translation invariant .png
In the above proof by Axler we read the following:

" ... ... Thus

... $\mid t + A \mid \leq \sum_{ k = 1 }^{ \infty } l ( t + I_k ) = \sum_{ k = 1 }^{ \infty } l ( I_k )$

Taking the infimum of the last term over all sequences $I_1, I_2, ... $ of open intervals whose union contains $A$, we have $\mid t + A \mid \leq \mid A \mid$. ... ..."Can someone please explain exactly how/why taking the infimum of the last term over all sequences $I_1, I_2, ... $ of open intervals whose union contains $A$, we have $\mid t + A \mid \leq \mid A \mid$ ... ?... Peter
 
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The inequality $|t+A| \leqslant \sum_{k=1}^\infty l(I_k)$ shows that $|t+A|$ is a lower bound for the set of sums of the form $\sum_{k=1}^\infty l(I_k)$. The inf of that set is by definition the greatest lower bound of the set. So any other lower bound, in particular $|t+A|$, is less than or equal to that inf.

Peter, it seems to me that most of your recent questions have been, in one form or another, instances of the general principle that "weak inequalities are preserved by limits": if every member of a set satisfies a weak inequality then the limit (or as in this case the sup or inf) of the set satisfies the inequality.
 
Thanks for a most helpful reply, Opalg ...

I think you are correct ...but then I am not used to thinking of sup and inf in terms of limits ...

Peter
 

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