Translational Momentum of a particle

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SUMMARY

The discussion focuses on calculating the translational momentum of a particle, specifically comparing an 80 kg person to a 1600 kg car moving at 1.2 km/h. The momentum formula, p = mv, is applied to find that the car's momentum is 1920 kg·km/hr. To achieve the same momentum, the person's velocity must be 24 km/hr. The discussion emphasizes equating the two momentum values to solve for the required velocity.

PREREQUISITES
  • Understanding of momentum calculation using the formula p = mv
  • Basic knowledge of unit conversions between kg·km/hr and kg·m/s
  • Familiarity with algebraic manipulation to solve equations
  • Concept of translational motion in physics
NEXT STEPS
  • Study the principles of momentum in classical mechanics
  • Learn about unit conversions between different measurement systems
  • Explore examples of momentum conservation in collisions
  • Investigate the implications of mass and velocity on kinetic energy
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of momentum and motion calculations.

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Suppose that your mass is 80 kg. How fast would you have to run to have the same translational momentum as a 1600 kg car moving at 1.2 km/h? I happen to know the answer is 24 km/hr. But, how do I get to this answer? What are the steps? Could someone solve it out and show me how they got it? Thanks a million!
 
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Momentum, which we denote by p, is simply the product of the mass and the velocity: p=mv. So since you know the mass and velocity of the car you can calculate its momentum and since you know what your mass is you can calculate what your velocity needs to be in order to have that same momentum.
 
The car's momentum is 1600*1.2 kg-km/hr? That being 1920. What would the units be?
Now my momentum is 80*Vu kg-km/hr where Vu is your velocity?
Where do I go from here?
 
Equate the two and solve for Vu. Momentum doesn't have a special unit in the SI system, it's usually just written as kg*m/s or sometimes N*s (the two are equivalent).
 

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